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vagabundo [1.1K]
3 years ago
12

PLEASE HELP, WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
exis [7]3 years ago
6 0
X_2 and y_2 are the values of your other coordinte point. Thus, x_2 = 6, and y_2 = 3.
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Find the area of the parallelogram.<br> 3 yd<br> 9 yd
Firlakuza [10]
27 yd2 (b•h) it’s just like a rectangle
4 0
3 years ago
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Bill spent 70 on fertilizer and weed killer for his lawn .Each pound of fertilizer cost 50 cents and each once of weed killer co
meriva

An equation that correctly represent this relationship if x represents the number of pounds of fertilizer and y the number of ounces of weed killer is  0.5x + 3.5y = 70

<u>Solution:</u>

Given that, Bill spent 70 on fertilizer and weed killer for his lawn

Each pound of fertilizer cost 50 cents and each once of weed killer cost 3.50

We have to write an equation, if x represents the number of pounds of fertilizer and y the number of ounces of weed killer.

Now,<em> total amount = amount for fertilizers + amount for weed killers.</em>

Total amount = number of pounds of fertilizers x cost per pound + number of ounces of weed killer x cost per ounce.

\begin{array}{l}{\rightarrow 70=x \times 0.50+y \times 3.50} \\\\ {\rightarrow 0.5 x+3.5 y=70}\end{array}

Hence, the equation is 0.5x + 3.5y = 70

5 0
3 years ago
Solve by finding the square root 2x^2=32
Cerrena [4.2K]

2x^2=32 so divide by 2 to make x^2=16 and the square root so x=4
8 0
3 years ago
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R * p = -37.8 <br>but also<br>r + p = 13.5<br><br>what would r be?<br>what would p be?
Nana76 [90]

R * p = -37.8


Solve for either R or p.


R = -37.8/p


Now plug into R + p = 13.5


-37.8/p + p = 13.5


Solve for p.


After finding p, plug your p-value into either R + p or R*p to find R.


Take it from here.




5 0
3 years ago
Read 2 more answers
Please help me ASAP
V125BC [204]
I'd say it's "convergent and doesn't have a sum"

because it's multiplying by 3 to get every new number and switching between ± after every new number. there is no sum because it's an infinite series.
8 0
4 years ago
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