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Marysya12 [62]
3 years ago
10

What is the 32nd term of the arithmetic sequence where a1 = 14 and a13 = -58?

Mathematics
1 answer:
liq [111]3 years ago
5 0
The nth term of an arithmetic sequence is found from:
n_{th}\ term=a+(n-1)d
Plugging in the given values, we get for the 13th term:
-58=14+12d
12d =-58 - 14 = -72
d = -6
So, the 32nd term is:
a_{32}=14+(32-1)-6=-172
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In the lab, Eric has two solutions that contain alcohol and is mixing them with each other. He uses 3 times as much Solution A a
Oduvanchick [21]

Answer:

Solution A = 2100

Solution B = 700

Step-by-step explanation:

Given that:

Let :

Millimeter of solution A = a

Millimeter of solution B = b

% alcohol, solution A =. 20% = 0.2

% alcohol solution B, = 14% = 0.14

Resulting millimeter of. Alcohol = 518

a = 3b - - - (1)

0.2a + 0.14b = 518 - - - - (2)

Put a = 3b in (2)

0.2(3b) + 0.14b = 518

0.6b + 0.14b = 518

0.74b = 518

b = 518 / 0.74

b = 700

a = 3b

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a = 2100

5 0
3 years ago
Which best describes a force?
mariarad [96]

Answer:

A vector with magnitude and direction

6 0
3 years ago
Suppose that y varies directly with x and inversely with z, and y = 4 when x = 8 and z = 14. find z when x = 36 and y = 6. first
raketka [301]

The value of z if x = 36 and y = 6 is 42

<h3>Direct and inverse variation</h3>

Suppose that y varies directly with x and inversely with z, hence the required expression will be:

y = kx/z

If  y = 4 when x = 8 and z = 14 then;

4 = k(8)/14

8k = 56

k = 7

To  find z when x = 36 and y = 6, we  will have:

6 = 7(36)/z
1 = 7(6)/z

z = 42

Hence the value of z if x = 36 and y = 6 is 42

Learn more on variation here: brainly.com/question/6499629

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6 0
1 year ago
Read 2 more answers
Need help plzz if ur answer wrong ill tell my friends who r mods and admins
AfilCa [17]

Answer:

C) 171.40

Step-by-step explanation:

The formula to find the volume of a rectangular prism is:

l x w x h = V

Substitute values:

4.2 x 5.3 x 7.7 = 171.40

So, there's your answer!

4 0
3 years ago
Read 2 more answers
A statistician selected a sample of 16 accounts receivable and determined the mean of the sample to be $5,000 with a standard de
Anon25 [30]

Answer:

The confidence level that was used is 0.25% .

Step-by-step explanation:

We are given that mean of the selected sample of 16 accounts is $5,000 and a standard deviation of $400.

It has also been reported that the sample information indicated the mean of the population ranges from $4,739.80 to $5,260.20. This represents the Confidence Interval for population mean.

<em>But we have to find that at what confidence level this information about range of population men has been stated.</em>

Since we know that Confidence Interval for population mean is given by :

   <em>C.I. for population mean = Sample mean(xbar) </em>\pm<em> z value * </em>\frac{Standard    deviation}{\sqrt{n} }<em />

i.e.,<em>if we have 95% C.I. = xbar </em>\pm<em> 1.96 * </em>\frac{\sigma}{\sqrt{n} }<em> .</em>

So, our Confidence Interval for population is written as :

 [$4,739.80 , $5,260.20] = $5000 \pm z value * \frac{400}{\sqrt{16} }

 $5000 - z value * 100 = $4739.80    { Solving these we get Z value = 2.602}

 $5000 + z value * 100 = $5260.20

In z table we find that at value of 2.60 the probability is 0.99534 so subtracting this from 1 we get confidence level for one tail i.e.0.5%(approx).

Therefore, for two tail Confidence level will be 0.5%/2 = 0.25% .

4 0
2 years ago
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