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3 years ago

What is the 32nd term of the arithmetic sequence where a1 = 14 and a13 = -58?

1 answer:

5 0

The nth term of an arithmetic sequence is found from:
$n_{th}\ term=a+(n-1)d$
Plugging in the given values, we get for the 13th term:
-58=14+12d
12d =-58 - 14 = -72
d = -6
So, the 32nd term is:
$a_{32}=14+(32-1)-6=-172$

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In the lab, Eric has two solutions that contain alcohol and is mixing them with each other. He uses 3 times as much Solution A a

Oduvanchick [21]

Answer:

Solution A = 2100

Solution B = 700

Step-by-step explanation:

Given that:

Let :

Millimeter of solution A = a

Millimeter of solution B = b

% alcohol, solution A =. 20% = 0.2

% alcohol solution B, = 14% = 0.14

Resulting millimeter of. Alcohol = 518

a = 3b - - - (1)

0.2a + 0.14b = 518 - - - - (2)

Put a = 3b in (2)

0.2(3b) + 0.14b = 518

0.6b + 0.14b = 518

0.74b = 518

b = 518 / 0.74

b = 700

a = 3b

a = 3(700)

a = 2100

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3 years ago

Which best describes a force?

mariarad [96]

Answer:

A vector with magnitude and direction

6 0

3 years ago

Suppose that y varies directly with x and inversely with z, and y = 4 when x = 8 and z = 14. find z when x = 36 and y = 6. first

raketka [301]

The value of z if x = 36 and y = 6 is 42

<h3>Direct and inverse variation</h3>

Suppose that y varies directly with x and inversely with z, hence the required expression will be:

y = kx/z

If y = 4 when x = 8 and z = 14 then;

4 = k(8)/14

8k = 56

k = 7

To find z when x = 36 and y = 6, we will have:

6 = 7(36)/z
1 = 7(6)/z

z = 42

Hence the value of z if x = 36 and y = 6 is 42

Learn more on variation here: brainly.com/question/6499629

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6 0

1 year ago

Read 2 more answers

Need help plzz if ur answer wrong ill tell my friends who r mods and admins

AfilCa [17]

Answer:

C) 171.40

Step-by-step explanation:

The formula to find the volume of a rectangular prism is:

l x w x h = V

Substitute values:

4.2 x 5.3 x 7.7 = 171.40

So, there's your answer!

4 0

3 years ago

Read 2 more answers

A statistician selected a sample of 16 accounts receivable and determined the mean of the sample to be $5,000 with a standard de

Anon25 [30]

Answer:

The confidence level that was used is 0.25% .

Step-by-step explanation:

We are given that mean of the selected sample of 16 accounts is $5,000 and a standard deviation of $400.

It has also been reported that the sample information indicated the mean of the population ranges from $4,739.80 to $5,260.20. This represents the Confidence Interval for population mean.

But we have to find that at what confidence level this information about range of population men has been stated.

Since we know that Confidence Interval for population mean is given by :

C.I. for population mean = Sample mean(xbar)  $\pm$  z value *  $\frac{Standard deviation}{\sqrt{n} }$ 

i.e.,if we have 95% C.I. = xbar $\pm$ 1.96 * $\frac{\sigma}{\sqrt{n} }$ .

So, our Confidence Interval for population is written as :

[$4,739.80 , $5,260.20] = $5000 $\pm$ z value * $\frac{400}{\sqrt{16} }$

$5000 - z value * 100 = $4739.80 { Solving these we get Z value = 2.602}

$5000 + z value * 100 = $5260.20

In z table we find that at value of 2.60 the probability is 0.99534 so subtracting this from 1 we get confidence level for one tail i.e.0.5%(approx).

Therefore, for two tail Confidence level will be 0.5%/2 = 0.25% .

4 0

2 years ago