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nikitadnepr [17]
3 years ago
9

A Rectangular‘s perimeter and it’s area have the same numerical value. The width of the rectangle is 3 units. What is the length

of the rectangle in units?
Mathematics
1 answer:
stiks02 [169]3 years ago
4 0

Answer:We found that the 6 by 3 rectangle works, because 6+3+6+3=18 and 6x3=18, so this has equal area and perimeter. ... But if both the length and the width are odd, then the area will be odd, meaning that it is impossible for the perimeter to be the same as the area.

Step-by-step explanation:

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Answer:

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3 0
3 years ago
Ay+6+4y-13=26 please solve for y
Harlamova29_29 [7]
The answer would be y= 33/a+4 I hope is helps.
8 0
3 years ago
Can i have help this it is the picture below
34kurt

Answer:

wow

Step-by-step explanation:

thats hard ikd

6 0
3 years ago
Read 2 more answers
Please help!!!!!!!!!
garri49 [273]
3x+50 = 6x - 10
6x -3x = 50+10
3x = 60
x = 20

answer
x = 20
4 0
3 years ago
Read 2 more answers
According to the U.S. Bureau of Labor Statistics, 20% of all people 16 years of age or older do volunteer work. In this age grou
Murljashka [212]

Answer:

1. P(X≥35) = 0.0183

2. P(X≤21) = 0.0183

3. P(0.18<p<0.25) = 0.7915

Step-by-step explanation:

We have the proportion for women: pw=0.22, and the proportion for men: pm=0.19.

1. We have a sample of 140 woman and we have to calculate the probability of getting 35 or more who do volunteer work.

This is equivalent to a proportion of

p=X/n=35/140=0.25

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.22*0.78}{300}}\\\\\\ \sigma_p=\sqrt{0.0006}=0.0239

We calculate the z-score as:

z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.25-0.22}{0.0239}=\dfrac{0.03}{0.0239}=0.8198

Then, the probability of having 35 women or more who do volunteer work in this sample of 140 women is:

P(X>35)=P(p>0.25)=P(z>2.0906)=0.0183

2. We have to calculate the probability of having 21 or fewer women in the group who do volunteer work.

The proportion is now:

p=X/n=21/140=0.15

We can calculate then the z-score as:

z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.15-0.2}{0.0239}=\dfrac{-0.05}{0.0239}=-2.0906

Then, the probability of having 21 women or less who do volunteer work in this sample of 140 women is:

P(X

3. For the sample with men and women, we use the proportion for both, which is π=0.2.

The sample size is n=300.

Then, the standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.2*0.8}{300}}\\\\\\ \sigma_p=\sqrt{0.0005}=0.0231

We can calculate the z-scores for p1=0.18 and p2=0.25:

z_1=\dfrac{p_1-\pi}{\sigma_p}=\dfrac{0.18-0.2}{0.0231}=\dfrac{-0.02}{0.0231}=-0.8660\\\\\\z_2=\dfrac{p_2-\pi}{\sigma_p}=\dfrac{0.25-0.2}{0.0231}=\dfrac{0.05}{0.0231}=2.1651

We can now calculate the probabilty of having a proportion within 0.18 and 0.25 as:

P=P(0.18

5 0
3 years ago
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