Answer:
m = - 8 ± 6
Step-by-step explanation:
Given
m² + 16m - 8 = 0 ( add 8 to both sides )
m² + 16m = 8
To complete the square
add ( half the coefficient of the m- term )² to both sides
m² + 2(8)m + 64 = 8 + 64
(m + 8)² = 72 ( take the square root of both sides )
m + 8 = ± 
= ± 
= ± 6
Subtract 8 from both sides
m = - 8 ± 6
The object reaches the lowest height at 5 seconds
<h3>How to determine the time?</h3>
The function is given as:
f(t) = -2t² +22t + 6
Differentiate the function
f'(t) = -4t +22
Set to 0
-4t +22 = 0
Subtract 22 from both sides
-4t = -22
Divide both sides by -4
t = 5.5
Remove decimal points
t = 5
Hence, the object reaches the lowest height at 5 seconds
Read more about quadratic functions at:
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First arrange numbers
14,15,15,17,19,20,21,23,24
19 is median
15+15/2=15 is first quartile
<u>Given</u>:
Given that the data are represented by the box plot.
We need to determine the range and interquartile range.
<u>Range:</u>
The range of the data is the difference between the highest and the lowest value in the given set of data.
From the box plot, the highest value is 30 and the lowest value is 15.
Thus, the range of the data is given by
Range = Highest value - Lowest value
Range = 30 - 15 = 15
Thus, the range of the data is 15.
<u>Interquartile range:</u>
The interquartile range is the difference between the ends of the box in the box plot.
Thus, the interquartile range is given by
Interquartile range = 27 - 18 = 9
Thus, the interquartile range is 9.
3x(3x-2y)
you have to find a common factor between the two numbers. in this case it's three, so you just divide each number by three.
