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love history [14]
3 years ago
5

A playground basketball court 9ft long and 46ft wide is to be resurfaced at a cost of $3.25 per sq ft. What will the resurfacing

cost?
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
7 0

first u multiply 94 ft times 46 ft to get the area. U get 4324. Next u multiply that by 3.25 to get the resurfacing cost

The answer is $14053.

Hope that helps!

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Please help please please
monitta

Answer:

x=10

y=-2

(10,-2)

Step-by-step explanation:

If X=10, we can put 10 in for x in the equation.

30 + 5y = 20

Next, we need to solve to find y.

We will get y on its own so we subtract 30 from 20 to get

5y=-10

We then know that 5 goes into -10 -2 times.

y=-2

5 0
3 years ago
15 + 10² • [12 – (12 – 3 • 2)] + 6
IRINA_888 [86]

[ Answer ]


10458


[ Explanation ]


Parenthesis

Exponents

Multiply

Divide

Add

Subtract



Parenthesis:

3 * 2 = 12

12 - 12 = 0

12 - 0 = 12


10^2 * 12


10 ^ 2 = 144

144 * 12 = 1728


1728 + 15 = 1743

1743 + 6 = 10458

7 0
3 years ago
Read 2 more answers
Please help me with this problem im having trouble answering this
adell [148]

Answer:

tgtftgrfrfrdrxdrdrcrcrcrxrxrxrc

4 0
3 years ago
Explain why 1/2 is not equivalent to 2/5.
juin [17]
Find ing the common denominator would make it 10.
for 1/2 to get to 10 you have to multiply by 5
1/2x5= 5/10
then you have to convert 2/5 to get the denominator to be 10
so you multiply 2/5 by 2
2/5x2= 4/10
5/10 is greater than 4/10
7 0
3 years ago
Read 2 more answers
The average age of staff in the maths department is 40.
pashok25 [27]

Answer:

Cerian is 28 years old

Step-by-step explanation:

The given parameters are;

The average age of the staffs in the mathematics department = 40

The number of staffs in the department = 7

The average age of Jill, Nicky and Wendy = 41

The average age of Andy, Alan and Cathy = 43

From the given parameters, we have;

The average age of the staffs in the mathematics department = (The sum total of the ages of the members of the math department)/(The number of staffs in the department)

Therefore;

40 = (The sum total of the ages of the members of the math department)/ (7)

From which we have;

The sum total of the ages of the members of the math department = 40 × 7 = 280

Which gives;

Jill's age + Nicky's age + Wendy's age + Cathy's age + Cerian's age + Alan's age + Andy's age = 280 years

The average age of Jill, Nicky and Wendy = 41

Given that Jill, Nicky, and Wendy make up 3 of the 7 members of staffs, we have;

The average age of Jill, Nicky and Wendy = (The sum total of the ages of Jill, Nicky, and Wendy)/(The number of staff Jill, Nicky, and Wendt make)

Therefore;

The sum total of the ages of Jill, Nicky, and Wendy = 41 × 3 = 123

Which gives;

Jill's age + Nicky's age + Wendy's age = 123 years

Similarly, the sum total of the ages of Andy, Alan, and Cathy = 43 × 3 = 129

Which gives;

Andy's age + Alan's age + Cathy's age = 129 years

Therefore;

Cerian's age = (Jill's age + Nicky's age + Wendy's age + Cathy's age + Cerian's age + Alan's age + Andy's age) - (Jill's age + Nicky's age + Wendy's age) + (Andy's age + Alan's age + Cathy's age)

∴ Cerian's age = 280 years - 123 years - 129 years = 28 years

6 0
3 years ago
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