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3 years ago

10

tim spends 25% of his time at the gym dooing leg exercises , 1/5 on shoulder exercises , 0.35 on biceps exercises , and warming

up . what percentage of time does tim spend warming up

1 answer:

svetoff [14.1K]3 years ago

3 0

Answer:

20%

Step-by-step explanation:

1/5 of 1 hour = 20 minutes

so 1/5 = 20%

25% + 20% = 45%

0.35 = 35%

45% + 35% = 80%

100% - 80% = 20%

Answer = 20%

Hope this helps!

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Math help for this question

dalvyx [7]

Answer:

im sorry i dont know but this is for a challenge sorry

Step-by-step explanation:

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3 years ago

The inverse of y = 3x – 2 would be:

Ber [7]

D because y=3x-2
Y+2=3x
Y+2/3=x

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3 years ago

Read 2 more answers

Suppose that 5 out of 13 people are to be chosen to go on a mission trip. In how many ways can these 5 be chosen if the order in

algol [13]

5 People can be chosen in 1287 ways if the order in which they are chosen is not important.

Step-by-step explanation:

Given:

Total number of students= 13

Number of Students to be selected= 5

To Find :

The number of ways in which the 5 people can be selected=?

Solution:

Let us use the permutation and combination to solve this problem

$nCr=\frac{(n)!}{(n-r)!(r)!}$

So here , n =13 and r=5 ,

So after putting the value of n and r , the equation will be

$13C_5=\frac{(13)!}{(13-5)!(5)!}$

$13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}$

$13C_5=\frac{(13 \times12 \times11 \times10 \times9 )}{((5 \times4 \times3 \times2 \times1)}$

$13C_5=\frac{154440}{120}$

$13C_5= 1287$

8 0

4 years ago

Question 2 (Essay Worth 10 points)

sashaice [31]

Ryan is correct, the mean is about 8.1.

To find the mean, you have to add up all the values, then divide by the total amount.

For Sample A:
60 x 6 + 90 x 7 + 145 x 8 + 150 x 9 + 55 x 10 = 4050

If you add up all the adults, you have 500.

Dividing 4050 by 500 = 8.1

Sample B will produce a very similar result.

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3 years ago

Find the LCM of the following

Tresset [83]

Answer:

A. LCM of 6,9, and 15 is 90.

B. LCM of 3,12, and 16 is 48.

C. LCM of 8,9, and 12 is 72.

D. LCM of 24 and 18 is 72.

E. LCM of 21 and 28 is 84.

F. LCM of 19 and 42 is 798.

Step-by-step explanation:

Hope this helps! :)

8 0

3 years ago