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2 years ago

I desperately need help ILL GIVE BRAINLIEST AND 50 points

Mathematics

1 answer:

otez555 [7]2 years ago

5 0

is this like Algebra 1 or 2? you can try to use a graph generator to help

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Ahmed is solving the following equation for xxx.

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

An extraneous solution is a root of a transformed equation which is not a root of the original equation because it was not included in the domain of the original equation.

Ahmed is solving $2\sqrt[3]{x-7}+11=3$ for x.

His steps were:

$\begin{aligned}2\sqrt[3]{x-7}&=-8\\ \sqrt[3]{x-7}&=-4\\ \left(\sqrt[3]{x-7}\right)^3&=(-4)^3\\ x-7&=-64 \end{aligned}$

Since cube roots <u>do not give two solutions when solved</u>, it is <u>not necessary </u>to check his answers for extraneous solutions.

7 0

2 years ago

The probability of winning a game is 40%. You play 60 times. How many times do you expect win? PLZZZZZ HELP MEEE!!!!

Molodets [167]

You espect wint the 40% of 60:
40% of 60=(40/100)*60=(40*60)/100=24

Answer: you expect win 24 times.

4 0

2 years ago

Read 2 more answers

A^2 + b^2 + c^2 = 2(a − b − c) − 3. (1) Calculate the value of 2a − 3b + 4c.

Verdich [7]

Answer:

$2a - 3b + 4c = 1$

Step-by-step explanation:

Given

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Required

Determine $2a - 3b + 4c$

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Open bracket

$a^2 + b^2 + c^2 = 2a - 2b - 2c - 3$

Equate the equation to 0

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 3 = 0$

Express 3 as 1 + 1 + 1

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 1 + 1 + 1 = 0$

Collect like terms

$a^2 - 2a + 1 + b^2 + 2b + 1 + c^2 + 2c + 1 = 0$

Group each terms

$(a^2 - 2a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

Factorize (starting with the first bracket)

$(a^2 - a -a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$(a(a - 1) -1(a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1) (a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + b+b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b(b + 1)+1(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + c+c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c(c + 1)+1(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)^2) = 0$

Express 0 as 0 + 0 + 0

$(a - 1)^2 + (b + 1)^2 + (c + 1)^2 = 0 + 0+ 0$

By comparison

$(a - 1)^2 = 0$

$(b + 1)^2 = 0$

$(c + 1)^2 = 0$

Solving for $(a - 1)^2 = 0$

Take square root of both sides

$a - 1 = 0$

Add 1 to both sides

$a - 1 + 1 = 0 + 1$

$a = 1$

Solving for $(b + 1)^2 = 0$

Take square root of both sides

$b + 1 = 0$

Subtract 1 from both sides

$b + 1 - 1 = 0 - 1$

$b = -1$

Solving for $(c + 1)^2 = 0$

Take square root of both sides

$c + 1 = 0$

Subtract 1 from both sides

$c + 1 - 1 = 0 - 1$

$c = -1$

Substitute the values of a, b and c in $2a - 3b + 4c$

$2a - 3b + 4c = 2(1) - 3(-1) + 4(-1)$

$2a - 3b + 4c = 2 +3 -4$

$2a - 3b + 4c = 1$

7 0

3 years ago

Solve 7x2(x + 1) = 6x + 14<br> Ox=-12<br> Ox = 12<br> Ox= -16<br> Ox = 16

Evgen [1.6K]

$\large\displaystyle\text{$\begin{gathered}\sf 7x-2(x+1)=6x+4 \end{gathered}$}$

Use the distributive property to multiply −2 by x+1.

$\large\displaystyle\text{$\begin{gathered}\sf 7x-2x-2=6x+14 \end{gathered}$}$

Combine 7x and −2x to get 5x.

$\large\displaystyle\text{$\begin{gathered}\sf 5x-2=6x+14 \end{gathered}$}$

Subtract 6x on both sides.

$\large\displaystyle\text{$\begin{gathered}\sf 5x-2-6x=14 \end{gathered}$}$

Combine 5x and −6x to get −x.

$\large\displaystyle\text{$\begin{gathered}\sf -x-2=14 \end{gathered}$}$

Add 2 to both sides.

$\large\displaystyle\text{$\begin{gathered}\sf -x=14+2 \end{gathered}$}$

Add 14 and 2 to get 16.

$\large\displaystyle\text{$\begin{gathered}\sf -x=16 \end{gathered}$}$

Multiply both sides by −1.

$\large\displaystyle\text{$\begin{gathered}\sf x=-16 \ \ \to \ \ \ Answer \end{gathered}$}$

<h2>{ Pisces04 }</h2>

3 0

1 year ago

Read 2 more answers

The poplution of Las vegas, Nevada has been increasing at an annual rate of 7.0%. If the poplution of las vegas was 478,434 in t

bearhunter [10]

Where x is years after 1999, the population is predicted to be ...
p(x) = 478,434*1.07^x

For x=11, this is
p(11) = 478,434*1.07^11 ≈ 1,007,033

The relation predicts the Las Vegas population in 2010 to be 1,007,033.

5 0

2 years ago