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Nezavi [6.7K]
4 years ago
8

ON A TIME LIMIT PLEASE ANWSER!! WILL GIVE BRAINLEST MARK

Mathematics
2 answers:
galben [10]4 years ago
6 0

Answer:

(0, 13) and (10,0)

Step-by-step explanation:

these points form a line that moves through th mostamount of points creating the highest corilation

timofeeve [1]4 years ago
5 0

Answer:

1,6 and 6,0 i think

Step-by-step explanation:

You might be interested in
Options for first blank: V=PR V=(PR)^(1/2) V=P^2R Options for second blank 16 5 4
oksano4ka [1.4K]

Answer:

The formula to find the voltage is:

v=\sqrt{P*R}

And the voltage is 4 volts

Step-by-step explanation:

To get the equation of voltage you need to isolate v in one side of the equation. In order to do that, you need to remove the divisor/denominator and its square. How will you do that?

First, multiply both sides with R:

P*R=\frac{v^{2} }{R} *R

That would result into removing the divisor R from the right side of the equation:

P*R=v^{2}

Next, square-root both sides:

\sqrt{P*R} =\sqrt{v^{2} }

That would result in removing the square of v from the right side of the equation:

\sqrt{P*R} =v

Thus we get the equation, v=\sqrt{P*R}.

To find out the voltage, simply replace R with 32 and P with 0.5

v=\sqrt{0.5*32}

r=\sqrt{16}

r=4

Thus, the voltage is 4 volts.

4 0
3 years ago
Can some help me im gonna fail the class if i dont get this question correct :(
kramer

Answer:

1

Step-by-step explanation:

2

3 0
3 years ago
Clothing sizes are not standardized across brands. Suppose that a large study of women's size 14 jeans revealed that the mean hi
kenny6666 [7]

Using the z-distribution, we have that:

  • The mean hip measurement for the random sample of 15 pairs of women's size 16 jeans is of 44.1 inches.
  • The <u>margin of error</u> is of 0.8 in.
  • The interpretation is: Mallorie is 99% sure that the mean hip measurement of size 16 jeans is between 43.3 in and 44.9 in.

The first step to solve this question, before building the confidence interval, is finding the sample mean, which is the <u>sum of all observations divided by the number of observations</u>. Hence:

\overline{x} = \frac{44.5+43.0+46.6+42.9+43.7+43.9+42.4+43.2+43.1+44.4+46.1+44.7+44.4+43.9+44.7}{15} = 44.1

The margin of error of a z-confidence interval is given by:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • z is the critical value.
  • \sigma is the population standard deviation.
  • n is the sample size.

We have to find the critical value, which is z with a p-value of \frac{1 + \alpha}{2}, in which \alpha is the confidence level.

In this problem, \alpha = 0.99, thus, z with a p-value of \frac{1 + 0.99}{2} = 0.995, which means that it is z = 2.575.

Then, the margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

M = 2.575\frac{1.2}{\sqrt{15}}

M = 0.8

The <u>margin of error</u> is of 0.8 in.

The interval is:

\overline{x} \pm M

\overline{x} - M = 44.1 - 0.8 = 43.3

\overline{x} + M = 44.1 + 0.8 = 44.9

The interpretation is:

Mallorie is 99% sure that the mean hip measurement of size 16 jeans is between 43.3 in and 44.9 in.

A similar problem is given at brainly.com/question/25300297

6 0
3 years ago
1. If 50 students in a college dorm with 500 students develop influenza during one month, what is the proportion of students who
ivanzaharov [21]
The proportion is 1:10. You can get this by dividing both 50 and 500 by 50.
7 0
2 years ago
Let T:P3→P3 be the linear transformation such that T(â’2x2)=3x2+4x, T(0.5x+3)=â’3x2+3xâ’4, and T(2x2â’1)=â’3x+4. Find T(1), T(
balu736 [363]

It looks like we're told that

T(-2x^2)=3x^2+4x

T\left(\dfrac12x+3\right)=-3x^2+3x-4

T(2x^2-1)=-3x+4

We use the fact that T is linear to find T(1),T(x),T(x^2). First, we notice that

T(-2x^2)+T(2x^2-1)=T(-2x^2+2x^2-1)=T(-1)=-T(1)

We also have

T\left(\dfrac12x+3\right)=T\left(\dfrac12x\right)+T(3)=\dfrac12T(x)+3T(1)

T(2x^2-1)=T(2x^2)-T(1)=2T(x^2)-T(1)

So once we find T(1), we can determine T(x) and T(x^2). We have

T(1)=-\left(T(-2x^2)+T(2x^2-1)\right)\implies T(1)=-3x^2-x-4

and using this we find

T(x)=12x^2+12x+16

T(x^2)=-\dfrac32x^2-2x

Then

T(ax^2+bx+c)=T(ax^2)+T(bx)+T(c)=aT(x^2)+bT(x)+cT(1)

T(ax^2+bx+c)=-\dfrac32\left(a-8b+2c\right)x^2-(2a-12b+c)x+16b-4c

8 0
4 years ago
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