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natta225 [31]
3 years ago
6

Right angle FCD intersects Line A B and Ray C E at point C. AngleFCE is congruent to AngleECD. AngleECD is complementary to Angl

eDCB. A horizontal line has points A, C, B. Right angle F C D intersects the line at point C. A line extends from point C vertically to point E. Angle A C F is 45 degrees and angle F C D is 90 degrees. Which statement is true about AngleDCB and AngleACF? They are congruent and complementary. They are congruent and supplementary. They are complementary but not necessarily congruent. They are supplementary but not necessarily congruent.
Mathematics
2 answers:
AlexFokin [52]3 years ago
5 0

Answer:

A: They are congruent and complementary.

Step-by-step explanation:

Just took the test hope this helps :D

Vladimir [108]3 years ago
3 0

Answer:

A

Step-by-step explanation:

it was correct on edge2020 so

(shrug)

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Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16).
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A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.
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Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

t=\sqrt{\frac{2h}{a}} ,where h=height of release

a=acceleration

a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}

Where I=moment of inertia

a for hoop

a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}

a=\frac{g\sin \theta }{2}

a for Uniform solid cylinder

a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}

a=\frac{2g\sin \theta }{3}

a for spherical shell

a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}

a=\frac{3g\sin \theta }{5}

a for Uniform Solid

a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}

a=\frac{5g\sin \theta }{7}

time taken will be inversely proportional to the square root of acceleration

t_1=k\sqrt{2}=1.414k

t_2=k\sqrt{\frac{3}{2}}=1.224k

t_3=k\sqrt{\frac{5}{3}}=1.2909k

t_4=k\sqrt{\frac{7}{5}}=1.183k

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

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