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Nuetrik [128]
3 years ago
11

What is the effective annual rate for an APR of 10.60 percent compounded quarterly?

Mathematics
1 answer:
Musya8 [376]3 years ago
7 0

Answer:

<em>The effective annual rate is 11.03%</em>

Step-by-step explanation:

The effective interest rate is calculated through the formula:

r = (1 + i/n)^n - 1

In this formula, r represents the effective interest rate, i represents the stated interest rate or APR, and n represents the number of compounding periods per year.

For a quarterly compounded interest, n=4. The APR i=10.60%=0.106

Given an APR r, the effective annual rate for a quarterly compound is:

r = (1 + 0.106/4)^4 - 1=1.0265^4-1

r=1.11029-1=0.1103

The effective annual rate is 11.03%

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The average density of Styrofoam is 1.00 kg/m^3. If a Styrofoam cooler is made with outside dimensions of 50.0 x 35.0 x 30.0 cm
Nadusha1986 [10]

Answer:

View graph

Step-by-step explanation:

The closest by default to 1100 cubic inches is taking two side and two front covers and that would give you 1080.12 cubic inches since two of the covers you must subtract 3 cm per side and side which would add 6 cm in total so outside would be 35 cm and indoor 29 cm . According the graph

29*50*3= 4350 * 2 lid = 8700 cm3

30*50*3= 4500*2 lid = 9000 cm3

So 8700+9000 = 17700 cm3 to inches 3 = 1080.12 cm3

5 0
3 years ago
Confused from where I left off PLEASE help
Leviafan [203]

Not sure the right equation so i did both....

#1 - √12m√15m=1m√2

Simplifies to:

13.416408m2=1.414214m

Let's solve your equation step-by-step.

13.416408m2=1.414214m

Step 1: Subtract 1.414214m from both sides.

13.416408m2−1.414214m=1.414214m−1.414214m

13.416408m2−1.414214m=0

Step 2: Factor left side of equation.

m(13.416408m−1.414214)=0

Step 3: Set factors equal to 0.

m=0 or 13.416408m−1.414214=0

m=0 or m=0.105409

Answer:  m=0 or m=0.105409


#2 - √12m√15m

Simplifies to:

13.416408m2

=13.416408*m2

=13.416408*(m*m)

=13.416408m2


Can I get a brainliest Please & Thank you...

4 0
3 years ago
Read 2 more answers
Guys i need your HELP ASAP​
ivanzaharov [21]
To solve this, you’ll first need to solve for their slopes.

The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3

We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3

The equation you get it y = 1/3x + b.

Now you will need to solve for b by substituting in the first ordered pair of line R.

2 = 1/3(1) + b.

Once you solve for b, you should get 5/3 and y = 1/3x + 5/3

Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.

y = 1/3(10) + 5/3.

Your solution should be 5.

So your answer is: a = 5
8 0
3 years ago
A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0&lt;=t&lt;=60
Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0
3 years ago
Which set of ordered pairs represent a function
spayn [35]
The 3rd set, no x or y numbers are repeated.

3 0
3 years ago
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