Answer:
View graph
Step-by-step explanation:
The closest by default to 1100 cubic inches is taking two side and two front covers and that would give you 1080.12 cubic inches since two of the covers you must subtract 3 cm per side and side which would add 6 cm in total so outside would be 35 cm and indoor 29 cm
. According the graph
29*50*3= 4350 * 2 lid = 8700 cm3
30*50*3= 4500*2 lid = 9000 cm3
So 8700+9000 = 17700 cm3 to inches 3 = 1080.12 cm3
Not sure the right equation so i did both....
#1 - √12m√15m=1m√2
Simplifies to:
13.416408m2=1.414214m
Let's solve your equation step-by-step.
13.416408m2=1.414214m
Step 1: Subtract 1.414214m from both sides.
13.416408m2−1.414214m=1.414214m−1.414214m
13.416408m2−1.414214m=0
Step 2: Factor left side of equation.
m(13.416408m−1.414214)=0
Step 3: Set factors equal to 0.
m=0 or 13.416408m−1.414214=0
m=0 or m=0.105409
Answer: m=0 or m=0.105409
#2 - √12m√15m
Simplifies to:
13.416408m2
=13.416408*m2
=13.416408*(m*m)
=13.416408m2
Can I get a brainliest Please & Thank you...
To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
Answer:
The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Step-by-step explanation:
Consider the provided information.
A chemical flows into a storage tank at a rate of (180+3t) liters per minute,
Let
is the amount of chemical in the take at <em>t </em>time.
Now find the rate of change of chemical flow during the first 20 minutes.

![\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B20%7D_%7B0%7D%20%7Bc%27%28t%29%7D%20%5C%2C%20dt%20%3D%5Cleft%5B180t%2B%5Cdfrac%7B3%7D%7B2%7Dt%5E2%5Cright%5D%5E%7B20%7D_0)


So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
The 3rd set, no x or y numbers are repeated.