Answer:
The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344
Step-by-step explanation:
56% of the students are involved in a sport team
56% = 0.56
According to the question, it is stated that 24% of the students at the school that are involved in a sports team also participated in the prom dance.
24% = 0.24
This means that we are going to find 24% of the original 56%, since 24% of them also participated in the prom dance.
The probability that a student who is involved in a sports team also participated in the prom dance = 0.24 * 0.56
The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344
Answer:
i think it is the multiplicative identiy property
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
x²+2x-15 = x²-3x+5x-15 = x(x-3)+5(x-3)=(x+5)(x-3)
or delta:
∆=2²-4*1*(-15)=4+60=64
√∆=8
x1 = (-2+8)/2 = 3
x2=(-2-8)/2=-5
and 4x+20 = 4(x+5)
The same is (x+5), so it is GCF. answer C
For 4 copies, the total cost for preparing and printing will be the same.
Step-by-step explanation:
Let,
p be the number of pages
Company A;
Charges of preparing = $6
Charges of per page print = $2.50
A(p)= 2.50p + 6 Eqn 1
Company B;
Charges of preparing = $4
Charges of per page print = $3
B(p)= 3p + 4 Eqn 2
For equaling the cost;
A(p) = B(p)

Dividing both sides by -0.50

For 4 copies, the total cost for preparing and printing will be the same.
Keywords: Addition, division
Learn more about division at:
#LearnwithBrainly