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Naddika [18.5K]
3 years ago
8

Item 19 A plant has an initial height of 1 inch and grows at a constant rate of 3 inches each month. A second plant that also gr

ows at a constant rate has an initial height of 4 inches and is 28 inches tall after 1 year. After how many months are the plants the same height?
Mathematics
1 answer:
Alex777 [14]3 years ago
3 0
3 months, i just answered this same question lol.
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An unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6
SIZIF [17.4K]

Answer:

Probability of rolling at least 4 sixes is 0.01696.

Step-by-step explanation:

We are given that an unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6  times.

The above situation can be represented through binomial distribution;

P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......

where, n = number trials (samples) taken = 6 trials

            r = number of success = at least 4

           p = probability of success which in our question is probability of

                 rolling a “six", i.e; p = 0.20

<u><em>Let X = Number of sixes on a die</em></u>

So, X ~ Binom(n = 6, p = 0.20)

Now, Probability of rolling at least 4 sixes is given by = P(X \geq 4)

P(X \geq 4) = P(X = 4) + P(X = 5) + P(X = 6)

=  \binom{6}{4} \times 0.20^{4} \times (1-0.20)^{6-4}+\binom{6}{5} \times 0.20^{5} \times (1-0.20)^{6-5}+\binom{6}{6} \times 0.20^{6} \times (1-0.20)^{6-6}

=  15 \times 0.20^{4} \times 0.80^{2}+6 \times 0.20^{5} \times 0.80^{1}+1 \times 0.20^{6} \times 0.80^{0}

=  0.0154 + 0.00154 + 0.000064

=  0.01696

<em />

Therefore, probability of rolling at least 4 sixes is 0.01696.

8 0
3 years ago
HURRY STRANGERS PLEASE I REALLY NEED THIS!!! A paper manufacturer is evaluating their packing procedures. Currently, they packag
drek231 [11]

Answer:

Step-by-step explanation:

Base on my own understanding what should be done is that three stacks will not work, because it wont be a symmetric arrangement and also one will be left out. So, two stacks of five each would be better and easy to carry. But the stacks should be arranged in such a manner that the lengths will be parallel to each other and not in-line which would increase the length making it comparatively very long. its easier to hold a (2*8.5,11,2*5=17,11,17) compact box, because it will be easy to carry a long and not heavy.

7 0
3 years ago
Un<br> How many solutions does this system have?<br> 12x-4y=-8<br> y=3x+2
Talja [164]

Answer:

Infinite

Step-by-step explanation:

Get both in the form y = first.

12x - 4y = -8

-4y = -8 - 12x

y = 2 + 3x

y = 3x + 2

These are the same line so all points are the same so that means there are infinite answers.

If ONLY the number in front of the x was the same there would be 0 answers, they would be parallel lines, and if the number in front of the xs were different there would only be one answer.  

3 0
3 years ago
17. One day when Terry went to school the temperature outside was –15 degrees Fahrenheit. In Terry's classroom the temperature w
docker41 [41]
C.+83 degrees. 68-(-15)=+83
5 0
3 years ago
I did the first one but can you help me with the second one plz??
yanalaym [24]

the only like-terms are on the right-hand-side, since the left-hand-side has only 1 term anyway.

\bf \cfrac{5}{2}s=\cfrac{3}{2}s+s\implies \cfrac{5}{2}s=\cfrac{3}{2}s+\cfrac{s}{1}\implies \cfrac{5}{2}s=\stackrel{\textit{using the LCD of 2}}{\cfrac{(1)3s+(2)s}{2}} \\\\\\ \cfrac{5}{2}s=\cfrac{3s+2s}{2}\implies \cfrac{5}{2}s = \cfrac{5}{2}s

5 0
3 years ago
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