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4 years ago

15

Write an addition expression that equals 8. Use at least 1 zero pair (i think I’m just slow lol)

2 answers:

elena55 [62]4 years ago

8 0

The answer is 8 use at least one zero I hope you get it right good luck I don't know If it is right good luck

lina2011 [118]4 years ago

7 0

Answer:

8 use at least one zero That what they said in my math class I hope the answer right

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Which one is the answer???

-Dominant- [34]

D is correct because y on I doesn't equal y on II.

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4 years ago

What is the solution of the proportion? 14/12 = D/48<br> a. 56<br> b. 672<br> c. 168<br> d. 576

Verdich [7]

So basically we can simplify the fraction by finding the gcf which is the greatest common factor so 14/12 both have 2 in common we simplify that by dividing by 2 so 14÷2 is 7/6 is the fraction on the left hand side and d/48 is the fraction on the right hand side so to solve for d we have to divide 336/6 whixh equals 56 as tour answer. Hoped this helped!!

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4 years ago

Read 2 more answers

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago

Which of the following best states the author's purpose?

Anastasy [175]

The answer is the second one

5 0

3 years ago

What type of triangle has side lengths 4, 4 squared 15, and 16?

zloy xaker [14]

Answer:

acute triangle

because you have 2 tall sides and 1 short

7 0

3 years ago