Answers:
- The lengths of sides PQ and RS are <u> 13 </u>
- The lengths of sides QR and SP are <u> </u><u>20 </u>
This is a 13 by 20 rectangle.
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Explanation:
Refer to the drawing below.
Let x be the length of side SP. Since we're dealing with a rectangle, the opposite side is the same length. Side QR is also x units long.
We're told that RS = SP - 7 which is the same as saying RS = x-7
We also know that PQ = x-7 as well because PQ is opposite side RS.
In short, we have these four sides in terms of x
- PQ = x-7
- QR = x
- RS = x-7
- SP = x
as shown in the drawing. The four sides add up to the perimeter of 66.
PQ+QR+RS+SP = perimeter
PQ+QR+RS+SP = 66
(x-7)+x+(x-7)+x = 66
4x-14 = 66
4x = 66+14
4x = 80
x = 80/4
x = 20
Use this x value to find the unknown side lengths.
- PQ = x-7 = 20-7 = 13
- QR = x = 20
- RS = x-7 = 20-7 = 13
- SP = x = 20
In short, this is a 13 by 20 rectangle.
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Check:
perimeter = side1+side2+side3+side4
perimeter = PQ+QR+RS+SP
perimeter = 13+20+13+20
perimeter = 33+33
perimeter = 66
The answer is confirmed.
Answer:
130/l in where l is the length of the rectangle
Step-by-step explanation:
The formula for area of a rectangle is length by width where the width is the height of the rectangle
Given that area=130 in²
Lets assume the length of this rectangle is =l inches
Then ;
A=l*w
130 =l*w
130/l = w
130/l in = height
Range is all real numbers
(-infinity, positive infinity)
I think its C. 7x3 = 21. 7x18 = 126. 9x7 = 63
If you all that the answer its 210. If you estimate what that little part above the farthest to the right shape, I'd say its near 18 to 21. Then add 210 with either numbers 18 through 21, it would be close to 227 square meters.