Question

JKLM is a parallelogram. Find m

Answer 1

Answer:

m∡L = 51°

Step-by-step explanation:

In any parallelogram, the sum of the angle measures on one side is 180°.

Therefore we have the equation:

$(2z-3)^o+(5z-6)^o=180^o$

Let's skip the degree marks and parentheses

$2z-3+5z-6=180$             combine like terms

$(2z+5z)+(-3-6)=180$

$7z-9=180$            add 9 to both sides

$7z-9+9=180+9$

$7z=189$           divide both sides by 7

$\dfrac{7z}{7}=\dfrac{189}{7}$

$z=27$

Put the value of z to the expression m∡L = (2z - 3)°:

$m\angle L=(2\cdot27-3)^o=(54-3)^o=51^o$

Answer 2

Good evening ,

Answer:

m∠L = 51°

Step-by-step explanation:

the sum of measures of angles of a parallelogram = 360°

2[(2z-3)+(5z-6)] = 360

⇔ 2[7z - 9] = 360 ⇔ 14z - 18 = 360 ⇔ 14z = 378 ⇔ z = 27

m∠L = 2z - 3 = 2(27) - 3 = 54 - 3 = 51.

:)