Answer: 1/2 which equals 50%
Step-by-step explanation:
Find the first semicircle area
Area semicircle can be determined by dividing the full area of circle by 2.
The first semicircle radius is 5 cm
semicircle area = 1/2 circle area
semicircle area = 1/2 × π × r²
semicircle area = 1/2 × 3.14 × 5²
semicircle area = 1/2 × 3.14 × 25
semicircle area = 39.25 cm²
Find the second semicircle area
Because the dimension of the second semicircle is congruent to the first semicircle, they have similar area measurement, 39.25 cm².
Find the quarter circle area
The area of quarter circle can be determined by dividing the full area of a circle by 4.
q circle = 1/4 × area of circle
q circle = 1/4 × π × r²
q circle = 1/4 × 3.14 × 10²
q circle = 1/4 × 314
q circle = 78.5 cm²
To find the entire area, add the area above together
area = first semicircle + second semicircle + q circle
area = 39.25 + 39.25 + 78.5
area = 157
The area of shaded region is 157 cm²
Answer: How to solve for similar triangles? The SAS rule states that two triangles are similar if the ratio of their corresponding two sides is equal and also, the angle formed by the two sides is equal. Side-Side-Side (SSS) rule: Two triangles are similar if all the corresponding three sides of the given triangles are in the same proportion.
Step-by-step explanation:
Answer:
1)49
2)231
Step-by-step explanation:
1)
4+9=13
4*2=8
8+1=9
2)
2+3+1=6
2+1=3
1*2=2
Answer:
The first three terms are -30, -27 and -24
Step-by-step explanation:
The formula for nth term of a arithmetic series is given by:
aₙ = a₁ + (n - 1)d
Substitute n = 16 in the given equation:
a₁₆ = a₁ + (16 - 1)d
Where aₙ = a₁₆ = 15. Substitute in the given equation
15 = a₁ + 15d ⇒ Equation (i)
Sum of arithmetic sequence is given by:
Sₙ = n(a₁ + aₙ) / 2
Substitute n = 16 in the above equation:
S₁₆ = 16(a₁ + a₁₆) / 2
Where S₁₆= -120 and a₁₆=15, substitute:
-120 = 16(a₁ + 15)/2
-240 = 16(a₁ +15)
-15 = a₁ + 15
a₁ = -30
Substitute it in Equation (i)
15 = a₁ + 15d
15 = -30 + 15d
15d = 15+30
d = 45/15
d = 3
So
a₁ = -30
a₂ = a₁ + (2-1)d
a₂ = -30 + 3
a₂ = -27
a₃ = a₁ + (3-1)d
a₃ = a₁ + 2d
a₃ = -30 + 2(3)
a₃ = -30 +6
a₃ = -24