All categories

3 years ago

Rewrite the expression as a multiple of a sum of two numbers with no common factor. 9+6

Mathematics

1 answer:

Zarrin [17]3 years ago

5 0

15 i dont know what u mean hope i helped bye

You might be interested in

Show that <img src="https://tex.z-dn.net/?f=%5Csqrt%7B20%7D%20%3D2%5Csqrt%7B5%7D" id="TexFormula1" title="\sqrt{20} =2\sqrt{5}"

Jobisdone [24]

Sqrt(20) = sqrt( 4*5) = 2 root(5)

Mark brainliest please

Hope this helps you

7 0

3 years ago

Find the m GEOMETRY 9th:)

maksim [4K]

Answer:

∠ WOT = 85

Step-by-step explanation:

To find the measure of ∠WOT

we know that ∠UOV is 180 in the pic

so by letting ∠WOT = x

∠UOT + ∠WOT + ∠WOV = 180

30 + x + 65 = 180

95 + x = 180

x = 180-95

x = 85

so ∠ WOT = 85

4 0

3 years ago

NEED HELP ASAP I WILL GIVE BRAINLIEST

inn [45]

Answer: It's the second option

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Can someone please show me how<br><br> 19169000*e^(0.15)= 222712201<br><br> When e= 2.7182818284?

Ierofanga [76]

Answer:

It doesn't. x = 22 271 201

Step-by-step explanation:

You are going to need a calculator no matter how you do it.

$x =19 169 000 \times e^{0.15}$

(a) The direct method

$x = 19 169 000\times 2.718 281 828^{0.15} = 19 169 000 \times 1.161 834 243 = 22 271 201$

(b) The indirect method

$\ln \left (19 169 000\times 2.718 281 828^{0.15} \right ) = \ln(19 169 000) + 0.15 = 16.768 805 + 0.15 = 16.918 804\\\\e^{16.918 804} = 22 271 201$

8 0

3 years ago

which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l

victus00 [196]

One equation for this would be

$y = \frac{41}{16} x-\frac{55}{8}$

We start by finding the slope between the two points:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}
\\
\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})
\\
\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})
\\
\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}$

A line parallel to this one will have the same slope. We will use point-slope form to write our equation:

$y-y_1=m(x-x_1)
\\
\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})
\\
\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}
\\
\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}
\\
\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}
\\
\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}
\\
\\y=\frac{41}{16}x-\frac{550}{80}
\\
\\y=\frac{41}{16}x-\frac{55}{8}$

6 0

3 years ago