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3 years ago

13

Rewrite the expression as a multiple of a sum of two numbers with no common factor. 9+6

1 answer:

Zarrin [17]3 years ago

5 0

15 i dont know what u mean hope i helped bye

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Jaila went to the butcher and bought 2.42 pounds of ground beef, ¾ pound of bacon, and 3 pork chops that each weigh .36 of a pou

kirill [66]

Answer: 4.25 pound of meat

Step-by-step explanation:

This is a addition questions, all you have to do is to add the numbers together. But you have to convert all the fractions and decimal to the same thing first. In this case, I'll convert all the fraction to decimal.

2.42 + 0.75 + 0.36 ✕ 3 = 4.25 pound

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2 years ago

James is studying different kinds of weather.

ivann1987 [24]

Answer:

i got b and h{i hope this helps}

Step-by-step explanation:

6 0

3 years ago

How many times does 10 go into 10000

vichka [17]

<span><u><em>The correct answer is: </em></u>
1000.

<u><em>Explanation</em></u><span><u><em>: </em></u>
We divide to find the answer to this: </span></span> $\frac{10000}{10}$ <span><span>. When we are dividing by 10, we can move the decimal to the left one place; doing this gives us 1000.</span></span>

6 0

3 years ago

A man is running a race. He starts a 0 and makes it to the 350 feet marker. It took him 7 minutes. How many feet can the man run

mel-nik [20]

350 divided by 7 is 50 so the man can run 50 feet in one minute

6 0

3 years ago

Under a certain transformation T, AA'BC' is the image of AABC. The perimeter of AA'B'C' is twice the perimeter of ABC. What kind

Anika [276]

The dimensions of the image are twice the dimensions of the preimage,

which indicates that the transformation is a dilation.

The transformation <em>T</em> is; <u>a dilation transformation with a scale factor of 2, D₂</u>

Reasons:

The transformation applied to ΔABC = T

The image of ΔABC following the transformation, T = ΔA'B'C'

The perimeter of ΔA'B'C' = Twice the perimeter of ΔABC

Therefore, we have;

A'B' + B'C' + A'C' = 2 × (AB + BC + AC)

Which gives

A'B' + B'C' + A'C' = 2·AB + 2·BC + 2·AC

By similar triangles, we have the ratio of corresponding sides as follows;

$\displaystyle \frac{AB}{A'B'} = \frac{BC}{B'C'} = \mathbf{ \frac{AC}{A'C'}}$

Which gives;

$\displaystyle \frac{AB}{A'B'} = \frac{AB}{2 \cdot AB} = \frac{1}{2}$

A'B' = 2·AB

Therefore;

Triangle ΔA'B'C' is twice the dimension of triangle ΔABC, and <em>T</em> is <u>a dilation transformation with a scale factor of 2, D₂</u>

Learn more about dilation transformation here:

brainly.com/question/2458912

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2 years ago