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3 years ago

Find the 52nd term of the following arithmetic sequence. 17, 22, 27, 32, ...

Mathematics

1 answer:

rewona [7]3 years ago

4 0

Answer:

17; 22; 27; 32

the terms increase by 5 each time

17 + 5 = 22 (the second term)

17 + 5 * 2 = 27 (third term)

So to get to the 52nd term, we have to add 5* 51 = 255 to 17

17 + 255 = 272

Step-by-step explanation:

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3 years ago

I need both of these.

Harman [31]

Answer:

Step-by-step explanation:

First method: for (x+3)^2 if you multiply (x+3)(x+3) you get x^2+6x+9 which doesn't equal x^2+9

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3 years ago

Find the sum to 40 terms of the arithmetic sequence below. Please show your<br> work.<br> 14+23+32

kirza4 [7]

Answer:

7580

Step-by-step explanation:

The formula for the sum of an arithmatic sequence is

$\frac{n}{2} (a_{1} + a_{n})$ ,

where n = total number of terms (in this case 40)

$a_{1}$ = the first term (in this case 14)

and $a_{2}$ = the last term (we will need to find this)

to find the last term, we can use this formula:

$a_{n} = a_{1} + (n-1)d$

where d is the difference between each term (in this case 9, because 23 - 14 = 9, and 32 - 23 = 9)

thus, $a_{n}$ = 14 + (40 - 1)9 = 14 + 39*9 = 14 + 351 = 365

plug this back into the first formula to get

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7 0

3 years ago

If <img src="https://tex.z-dn.net/?f=log_%7B2%7D" id="TexFormula1" title="log_{2}" alt="log_{2}" align="absmiddle" class="latex-

12345 [234]

Answer:

The answer is (1/2)z - x - 3y

Step-by-step explanation:

∵ $log_{2}P=x$

∵ $log_{2}Q=y$

∵ $log_{2}R=z$

∵ $log_{2}\frac{R^{\frac{1}{2}}}{(P)(Q^{3})}$

∴ $log_{2}(R)^{\frac{1}{2}}-log_{2}P-log_{2}(Q^{3})$

∴ $\frac{1}{2}log_{2}R-log_{2}P-3log_{2}Q$

∴ $\frac{1}{2}z-x-3y$

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4 years ago

Need help asap ! thanks

Softa [21]

3.33 is the right answer

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3 years ago

Read 2 more answers