I don't think anyone can solve this without seeing the table mentioned in the question :)
Answer:
The ratio of the amount for swordfish to the amount of salmon is 6:4
Step-by-step explanation:
Given as :
The price for 1 pound of swordfish = The price of 1.5 pound of salmon
So, On this relation
The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 ) pound of salmon
i.e The price for 2 pound of swordfish = The price of 3 pound of salmon
Now According to question
Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39
Let the money she pay for swordfish = 2 sw
And The money she pay for salmon = 3 sa
∵, The total money she pay for both = $ 39
I.e 2 sw + 3 sa = 39
As 2 sw = 3 sa
So, 3 sa + 3 sa = 39
Or, 6 sa = 39
or, sa =
= 
∴ sw =
× 
or, sw = 
Now, the ratio of the amount for swordfish to the amount of salmon = 
I.e The ratio = 
Hence The ratio of the amount for swordfish to the amount of salmon is 6:4
Answer
Answer:
L.H.S.
= (cos5a.sin2a-cos4a.sin3a)/ (sin5a.sin2a-cos4a.cos3a)
Multiply numerator and denominator by 2.
= 2(cos5a.sin2a - cos4a.sin3a) / 2(sin5a.sin2a - cos4a.cos3a)
= (2cos5a.sin2a - 2cos4a.sin3a)/
(2sin5a.sin2a - 2cos4a.cos3a) = [sin(5a+2a)-sin(5a-2a)-sin(4a+3a)
+sin(4a-3a)]/[cos(5a-2a)-cos(5a+2a)-sin(4a-3a) +cos(4a+3a)]
= (sina - sin3a)/(cso3a-cosa)
= (-2cos2a.sina)/(-2sin2a.sina)
= cos2a/sin2a
= cot2a
= R.H.S.
The percentage of walkers who got a ride is 37.5/3=12.5%
The number of that is 0.125*24=3 students.
Answer:
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