Xy = 6
x + y = 9
x + y = 9
x - x + y = -x + 9
y = -x + 9
xy = 6
x(-x + 9) = 6
x(-x) + x(9) = 6
-x² + 9x = 6
-x² + 9x - 6 = 0
-1(x²) - 1(-9x) - 1(6) = 0
-1(x² - 9x + 6) = 0
-1 -1
x² - 9x + 6 = 0
x = -(-9) ± √((-9)² - 4(1)(6))
2(1)
x = 9 ± √(81 - 24)
2
x = 9 ± √(57)
2
x = 4.5 ± 0.5√(57)
x + y = 9
4.5 ± 0.5√(57) + y = 9
- (4.5 ± 0.5√(57)) - (4.5 ± 0.5√(57))
y = 4.5 ± 0.5√(57)
(x, y) = (4.5 ± 0.5√(57), 4.5 ± 0.5√(57))
The two numbers that multiply to 6 and add up to 9 are 4.5 ± 0.5√(57).
You have a 1/3 chance each time you role
So 1/3 x 12 = 4 times that you would role a 5 or a 6
When you say either, you add both A and B
0.3+0.4=0.7
Your answer is 0.70 which means 70%
128 = a + + 4(a + 10) + (a + 10)
128 = a + 4a + 40 + a + 10
128 = 6a + 50
128-50 = 6a
78 = 6a
13 = a
1st = a = 13
2nd = 4(a + 10) = 4(23) = 92
3rd = a + 10 = 23
