Answer:
Step-by-step explanation:
7.5
Answer:
Step 1
Write and solve the inequality:
2,500 + 40a ≥ 4,000, or 40a ≥ 1,500
a ≥ 37.5
Step 2
If the shelter places 30 cats and 10 dogs,
or 40 animals, that will be enough to meet
its goal, because a = 40 is a solution to the
inequality a ≥ 37.5.
Answer:
I NEEEEEEEED TO SEEEE GRAPHHHHHHHHHHHH
Step-by-step explanation:
Answer:
50%
Step-by-step explanation:
So there are 90 2 digit numbers. There are 45 2 digit odd numbers.
The probability should be 50%
Answer:
34.6 units
Step-by-step explanation:
The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.
The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).
Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:
Distance between point A(-6, 2) and point B(2, 6):
![AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=%20AB%20%3D%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D%20)
Let,
![A(-6, 2)) = (x_1, y_1)](https://tex.z-dn.net/?f=%20A%28-6%2C%202%29%29%20%3D%20%28x_1%2C%20y_1%29%20)
![B(2, 6) = (x_2, y_2)](https://tex.z-dn.net/?f=%20B%282%2C%206%29%20%3D%20%28x_2%2C%20y_2%29%20)
![AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}](https://tex.z-dn.net/?f=%20AB%20%3D%20%5Csqrt%7B%282%20-%20%28-6%29%29%5E2%20%2B%20%286%20-%202%29%5E2%7D%20)
![AB = \sqrt{(8)^2 + (4)^2}](https://tex.z-dn.net/?f=%20AB%20%3D%20%5Csqrt%7B%288%29%5E2%20%2B%20%284%29%5E2%7D%20)
![AB = \sqrt{64 + 16} = \sqrt{80}](https://tex.z-dn.net/?f=%20AB%20%3D%20%5Csqrt%7B64%20%2B%2016%7D%20%3D%20%5Csqrt%7B80%7D%20)
(nearest tenth)
Distance between B(2, 6) and C(7, 1):
![BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=%20BC%20%3D%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D%20)
Let,
![B(2, 6) = (x_1, y_1)](https://tex.z-dn.net/?f=%20B%282%2C%206%29%20%3D%20%28x_1%2C%20y_1%29%20)
![C(7, 1) = (x_2, y_2)](https://tex.z-dn.net/?f=%20C%287%2C%201%29%20%3D%20%28x_2%2C%20y_2%29%20)
![BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}](https://tex.z-dn.net/?f=%20BC%20%3D%20%5Csqrt%7B%287%20-%202%29%5E2%20%2B%20%281%20-%206%29%5E2%7D%20)
![BC = \sqrt{(5)^2 + (-5)^2}](https://tex.z-dn.net/?f=%20BC%20%3D%20%5Csqrt%7B%285%29%5E2%20%2B%20%28-5%29%5E2%7D%20)
![BC = \sqrt{25 + 25} = \sqrt{50}](https://tex.z-dn.net/?f=%20BC%20%3D%20%5Csqrt%7B25%20%2B%2025%7D%20%3D%20%5Csqrt%7B50%7D%20)
(nearest tenth)
Distance between C(7, 1) and D(3, -5):
![CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=%20CD%20%3D%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D%20)
Let,
![C(7, 1) = (x_1, y_1)](https://tex.z-dn.net/?f=%20C%287%2C%201%29%20%3D%20%28x_1%2C%20y_1%29%20)
![D(3, -5) = (x_2, y_2)](https://tex.z-dn.net/?f=%20D%283%2C%20-5%29%20%3D%20%28x_2%2C%20y_2%29%20)
![CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}](https://tex.z-dn.net/?f=%20CD%20%3D%20%5Csqrt%7B%283%20-%207%29%5E2%20%2B%20%28-5%20-%201%29%5E2%7D%20)
![CD = \sqrt{(-4)^2 + (-6)^2}](https://tex.z-dn.net/?f=%20CD%20%3D%20%5Csqrt%7B%28-4%29%5E2%20%2B%20%28-6%29%5E2%7D%20)
![CD = \sqrt{16 + 36} = \sqrt{52}](https://tex.z-dn.net/?f=%20CD%20%3D%20%5Csqrt%7B16%20%2B%2036%7D%20%3D%20%5Csqrt%7B52%7D%20)
(nearest tenth)
Distance between D(3, -5) and A(-6, 2):
![DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=%20DA%20%3D%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D%20)
Let,
![D(3, -5) = (x_1, y_1)](https://tex.z-dn.net/?f=%20D%283%2C%20-5%29%20%3D%20%28x_1%2C%20y_1%29%20)
![A(-6, 2) = (x_2, y_2)](https://tex.z-dn.net/?f=%20A%28-6%2C%202%29%20%3D%20%28x_2%2C%20y_2%29%20)
![DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}](https://tex.z-dn.net/?f=%20DA%20%3D%20%5Csqrt%7B%28-6%20-%203%29%5E2%20%2B%20%282%20-%20%28-5%29%29%5E2%7D%20)
![DA = \sqrt{(-9)^2 + (7)^2}](https://tex.z-dn.net/?f=%20DA%20%3D%20%5Csqrt%7B%28-9%29%5E2%20%2B%20%287%29%5E2%7D%20)
![DA = \sqrt{81 + 49} = \sqrt{130}](https://tex.z-dn.net/?f=%20DA%20%3D%20%5Csqrt%7B81%20%2B%2049%7D%20%3D%20%5Csqrt%7B130%7D%20)
(nearest tenth)
Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units