Uh I’m not sure I’m so sorry the other guy gave you a answer tho!
I meant verb ...... Stupid auto correct
First list all the positive and negative factors of the constant term in the expression: ±(1,2,3,4,6,12) these will be the values for "p"
Second list all the positive and negative factors of the leading coefficient:
±(1,3) these will be the values for "q"
Now list all the possible values of

these will be the possible rational zeros of the polynomial function:
±(

)
these can be reduced to the following list:
±(1,

, 2,

, 3, 4,

, 6, 12
This list represents the possible rational zeros of the function. You can then use synthetic division to narrow down the actual roots of the function.
Answer:
3sqrt2
Step-by-step explanation:
b jhf vj fjvfd vmnd fmv ndkfv mndfvdf nkvvdf lkv nf khlfd hjvdf

The equations are :
The given pair of equations have infinitely many solutions.
(because the first equation is the product of second equation with -2)