One way to go about this is to first list everything we know in the form of variables. This will make it easier to see how these numbers correlate instead of trying to remember formulas to plug these numbers into.
TimeA = 2.4h (time of Car A to travel)
TimeB = 4h (time of Car B to travel)
SpeedA = SpeedB + 22mph (Speed of Car A<span>)
</span>SpeedB = SpeedA - 22mph (Speed of Car B<span>)
</span>Distance = x (the distance traveled by each car)
We are looking for SpeedA. How can we find this? Well, we know that speed multiplied by time is equal to distance, so let's start there.
SpeedA * 2.4h = x
<span>(SpeedB + 22mph) * 2.4h = x
</span>(2.4h * SpeedB) + 52.8miles = x
We also know that:
SpeedB * 4h = x
Since both of these equations are equal to x, we can combine them:
SpeedB * 4h = x = <span>(2.4h * SpeedB) + 52.8miles
</span>SpeedB * 4h = <span>(2.4h * SpeedB) + 52.8miles
</span>1.6h * Speed B = 52.8miles
SpeedB = 52.8/1.6 mph = 33 mph
<span>SpeedA = SpeedB + 22mph = 33mph + 22mph = 55mph
</span>
Therefore, Car A was traveling at 55mph.
Answer:
The answer would be: D. (1,2) and (2,-1)
Answer:
<u>Question 9</u>
Name the ordered pairs in the table: 3, 4, 5, 6, 7
Ordered pairs: (1,3), (2,4), (3,5), (4,6), (5,7)
Graph the equation: the attachment
Step-by-step explanation:
I don't know how to do questions 11 and 12.
Also sorry if these aren't correct.
I believe the answer would be angle O.
All you do to find this answer is rotate the 2nd figure so it matches the 1st one above it, and look to see which angles...I guess are where and which match each other.
Angle ABC = 48
Angle PBC = 24
Angle A + Angle C = 180-24. Angle A = Angle C
Angle C = 132/2 = 66
Angle PCD = 66-24 = 42 degrees
