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2 years ago

Solve the inequality for u. 55 > 4u + 15 Simplify your answer as much as possible.

Mathematics

1 answer:

valentinak56 [21]2 years ago

4 0

Step-by-step explanation:

55 > 4u + 15

40 > 4u

10 > u

so, this is true for all u < 10

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Find the coordinates of the missing endpoint if P is the midpoint of Line Segment NQ.

dimaraw [331]

Midpoint formula is $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$ .

So starting with this one, we will be solving for the coordinates of the unknown endpoint separately. Starting with the x-coordinate, since we know that the midpoint x-coordinate is 5 and the x-coordinate of N is 2, our equation is set up as such: $\frac{x+2}{2}=5$ From here we can solve for the x-coordinate of Q.

Firstly, multiply both sides by 2: $x+2=10$

Next, subtract both sides by 2 and your x-coordinate is $x=8$

With finding the y-coordinate, it's a similar process as with the x-coordinate except that we are using the y-coordinates of the midpoint and endpoint N.

$\frac{y+0}{2}=2\\ y=4$

<u>Putting it together, the missing endpoint is (8,4).</u>

<em>(The process is pretty much the same with the other problems, so I'll go through them real quickly.)</em>

$\frac{x+5}{2}=6\\ x+5=12\\ x=7$

$\frac{y+4}{2}=3\\ y+4=6\\ y=2$

<u>The missing endpoint is (7,2).</u>

$\frac{x+3}{2}=-1\\ x+3=-2\\ x=-5$

$\frac{y+9}{2}=5\\ y+9=10\\y=1$

<u>The missing endpoint is (-5,1).</u>

8 0

3 years ago

Use a table to identify three equivalent ratios of 2/5.

zlopas [31]

Answer: The simplest form of ratio 6:15=2×3:5×3=2:5

Step-by-step explanation: So, 2:5 is equivalent to 6:15.

7 0

1 year ago

Read 2 more answers

The cost of 2 cups of strawberries is $6. Write an equation for the relationship between the cost and cups os strawberries

Rasek [7]

Answer:One equation is x=6/2

Hope this helps

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3 years ago

Read 2 more answers

Please help solve for x..

aalyn [17]

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

$x^{100}-4^x \cdot x^{98}-x^2+4^x=0$

Factor out -1:

$\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0$

Divide both sides by -1:

$\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0$

Rearrange the terms:

$\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0$

$\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:$

$\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0$

Factor the first two terms and the last two terms separately:

$\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0$

Factor out the common term $(x^{98}-1)$ :

$\implies (4^x-x^2)(x^{98}-1)=0$

<u>Zero Product Property</u>: If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the <u>Zero Product Property</u>, set each factor equal to zero and solve for x (if possible):

$\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}$