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Inessa [10]
3 years ago
7

2n=4x+2y;nfind the variable n

Mathematics
1 answer:
Alenkinab [10]3 years ago
7 0

2n=4x+2y\qquad|\text{divide both sides by 2}\\\\n=\dfrac{4x}{2}+\dfrac{2y}{2}\\\\n=2x+y

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I am confused please can you help me
lorasvet [3.4K]
Domain x|x = -2, 2
range x|x = -1, 4
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Identify the indicated element
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<span>how do you identify the indicated elements for example
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8 0
4 years ago
Read 2 more answers
1. Which formula defines the sequence f(1)=2, f(2)= 6, f(3)= 10, f(4)= 14, f(5)= 18?
Natasha_Volkova [10]

Answer:

f(n) =4 + f(n-1) \\for\ n>2

Step-by-step explanation:

Given

f(1)=2\\ f(2)= 6\\ f(3)= 10\\ f(4)= 14\\ f(5)= 18

Required

Determine the formula

First, we need to solve common difference (d)

d = f(n) - f(n-1)

Take n as 2

d = f(2) - f(2-1)

d = 6 - 2

d = 4

Represent each function as a sum of the previous

f(1) = 2

f(2) = 2 + 4 = f(1) + 4

f(3) = 6 + 4 = f(2) + 4

f(4) = 10 + 4 = f(3) + 4

f(5) = 14 + 4 = f(4) + 4

Represent the function as f(n)

f(n) =f(n-1) + 4

Reorder

f(n) =4 + f(n-1) \\for\ n>2

7 0
3 years ago
Use the linear combination method to solve this system of equations. What is the value of x?
Semmy [17]
X=1 because when u put it in then u will find out.y=-1
7 0
3 years ago
Read 2 more answers
In a particular region, 6% of the population is thought to have a certain disease. A standard diagnostic test has been found to
pochemuha

Answer:

The positive predictive value ≈ 30.012%

Step-by-step explanation:

(a) The given percentage of the people in the region that have the disease, P(D) = 6% = 0.06

The percentage people correctly identified as having the disease by the standard diagnostic test = 91%

The percentage of people incorrectly identified as having the disease by the standard diagnostic test, P(T + |H) = 8%

Therefore, the sensitivity of the test, P(T + |D) = 0.91

The specificity of the test, P(T - |H) = 1 - 0.08 = 0.92

Therefore, the probability that a person is healthy, P(H) = 1 - 0.06 = 0.94

Therefore, in a population of 1,000 people, 60 people have the disease, with a sensitivity of 91%, the test will correctly pic 0.91×66 = 60.06 people correctly with the disease and 0.91 × 940 = 855.4 people without the disease

The number of non-diseased that test positive by the test is 0.08 × 1000 = 80 people which are false positives

Therefore, the number of diseased diagnosed as negative is 0.08 × 60 = 4.8

Therefore, we have;

\begin{array}{cccc}&Deseased&Non-diseased& Diseased + Non-diseased\\Test  \ +ve&60.06&80& 140.06\\Test \ -ve&4.8&855.4&\end{array}

The positive predictive value = Diseased +ve/(Diseased +ve + Non-diseased  +ve)

The \ positive \  predictive  \ value = \dfrac{Diseased +ve}{Diseased +ve + Non-diseased  +ve} \times 100

Therefore;

The positive predictive value = 60.06/(60.06 + 140.06) × 100 ≈ 30.012%

7 0
3 years ago
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