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barxatty [35]
3 years ago
5

write an equation in slop-intercept form for the line that passes through (-3,1) and is parallel to y=2x-4

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

The equation of line in slop-intercept form is given by:

y=2x+7

Step-by-step explanation:

Given equation of line:

y=2x-4

To find the equation of line parallel to the line of the given equation and passes through point (-3,1).

Applying slope relationship between perpendicular lines.

m_1=m_2

where m_1 and m_2 are slopes of parallel lines.

For the given equation in the form y=mx+b the slope m_2 can be found by comparing y=2x-4 with standard form.

∴ m_2=2

Thus slope of line parallel to this line m_1 would be given as:

∴ m_1=2

The line passes through point (-3,1)

Using point slope form:

y-y_1=m(x-x_1)

Where (x_1,y_1)\rightarrow (-3,1) and m=m_2=2

So,

y-1=2(x-(-3))

y-1=2(x+3)

Using distribution.

y-1=(2\times x)+(2\times 3)

y-1=2x+6

Adding 1 to both sides.

y-1+1=2x+6+1

y=2x+7

Thus the equation of line in slop-intercept form is given by:

y=2x+7

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