![\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}](https://tex.z-dn.net/?f=%5Cmathfrak%7B%5Chuge%7B%5Cpink%7B%5Cunderline%7B%5Cunderline%7BAnSwEr%3A-%7D%7D%7D%7D%7D)
Actually Welcome to the Concept of the Mathematics, this is called as function inside another function, just we have replace the condition of x here,
1)g(f(4)) = here, f(4) = 4-7= -3
so now, g(-3) = (-3)^2 =9
g(f(4)) = 9
2) f(g(4)) = 16-7 = 9
f(g(4))= 9
3) g(f(-1)) = 64
4) f(g(-1)) = -6
done.
Hi
The answer to this question is B 5.02
Hoped I Helped
Answer:
x = 2 1/3
y = 14 / (2 1/3) = 14 / (7/3) = 14*3/7 = 42/7 = 6
y = 6
x = 4 1/5
y = 14 / (4 1/5) = 14 / (21/5) = 14*5/21 = 70/21 = 3 7/21 = 3 1/3
y = 3 1/3
x = 7/6
y = 14 / (7/6) = 14*6 / 7 = 12
y = 12
Step-by-step explanation:
Given:
Hayden
minutes to complete each level of his video game.
He plays for
minutes.
To find:
The number of levels he will complete.
Solution:
We have,
Required time for each level = ![1\dfrac{1}{2}](https://tex.z-dn.net/?f=1%5Cdfrac%7B1%7D%7B2%7D)
Total time = ![10\dfrac{1}{4}](https://tex.z-dn.net/?f=10%5Cdfrac%7B1%7D%7B4%7D)
The number of level is
![n=\dfrac{\text{Total time}}{\text{Required time for each level}}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B%5Ctext%7BTotal%20time%7D%7D%7B%5Ctext%7BRequired%20time%20for%20each%20level%7D%7D)
![n=\dfrac{10\dfrac{1}{4}}{1\dfrac{1}{2}}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B10%5Cdfrac%7B1%7D%7B4%7D%7D%7B1%5Cdfrac%7B1%7D%7B2%7D%7D)
![n=\dfrac{\dfrac{10(4)+1}{4}}{\dfrac{1(2)+1}{2}}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B%5Cdfrac%7B10%284%29%2B1%7D%7B4%7D%7D%7B%5Cdfrac%7B1%282%29%2B1%7D%7B2%7D%7D)
![n=\dfrac{\dfrac{41}{4}}{\dfrac{3}{2}}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B%5Cdfrac%7B41%7D%7B4%7D%7D%7B%5Cdfrac%7B3%7D%7B2%7D%7D)
On further simplification, we get
![n=\dfrac{41}{4}\times \dfrac{2}{3}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B41%7D%7B4%7D%5Ctimes%20%5Cdfrac%7B2%7D%7B3%7D)
![n=\dfrac{41}{6}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B41%7D%7B6%7D)
![n=6.8333...](https://tex.z-dn.net/?f=n%3D6.8333...)
Number of levels must be a whole number. So, approx to value to the preceding whole number.
![n\approx 6](https://tex.z-dn.net/?f=n%5Capprox%206)
Therefore, Hayden will complete 6 levels if he plays for
minutes.
Answer:
The 95% confidence interval of the proportion of all adults that have high blood pressure is 0.17059 <
< 0.314695
Step-by-step explanation:
The confidence interval for a proportion is given by the following formula;
![CI=\hat{p}\pm z\times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}](https://tex.z-dn.net/?f=CI%3D%5Chat%7Bp%7D%5Cpm%20z%5Ctimes%20%5Csqrt%7B%5Cfrac%7B%5Chat%7Bp%7D%281-%5Chat%7Bp%7D%29%7D%7Bn%7D%7D)
Where:
x = 33
n = 136
= x/n = 33/136 = 0.243
z value for 95% confidence is 1.96
Plugging in the values, we have;
![CI=0.243\pm 1.96\times \sqrt{\frac{0.243(1-0.243)}{136}}](https://tex.z-dn.net/?f=CI%3D0.243%5Cpm%201.96%5Ctimes%20%5Csqrt%7B%5Cfrac%7B0.243%281-0.243%29%7D%7B136%7D%7D)
Which gives;
0.17059 <
< 0.314695
Hence the 95% confidence interval of the proportion of all adults that have high blood pressure = 0.17059 <
< 0.314695
From the above we have;
23.2 < x < 42.798
Since we are dealing with people, we round down as follows;
23 < x < 42.