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liraira [26]
2 years ago
15

Xavier left his house at time zero and

Mathematics
1 answer:
Lady_Fox [76]2 years ago
5 0

Answer:

Graph the points, (2,18) (7, 24) and (16, 0)

Step-by-step explanation:

Going to the store takes 2 minutes for 18 blocks, which is the first point

He stays at the store for 2 minutes then takes 3 minutes to get to the bank which is 6 blocks away, add the time together and blocks, and you get the second point

He stopped at the bank for 3 minutes and the drove back home. It takes him 6 minutes to get back home, (24/6), add all the minutes together and you get 16.

(This is assuming the graph is y for blocks and x for minutes)

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Alexxx [7]

Answer:

B.

Step-by-step explanation:

So, lets remember a few things first.

#1: The formula for finding the answer is A^2+B^2=C^2

#2: A is the opposite side, B is the adjacent side, and C is the hypotenouse side.

Now lets plug in what we already know, and see if we canf igure out the annswer:

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Now I am going to stop us here. This is your equation that will find the answer. In your question, they use x^2, A^2 is a variable you can use instead. But looking at this, answer B and my equation I wrote above are exactly the same.

If you want, here is how I further solved it, this might give you a better grasp on what to do for future problems:

Ok, not  too bad, the A is the unkown value, which is the opposite side.

Now, how do we figure this out? Well, we just need to sovle for A.

To do this, lets clean up our equation by first sqauring all the values(except for the unkown):

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Ok, that looks better, now lets just subtract the adjeacent side(b), which is 144, from the hypotenouse side(c), which is 169.

This will now look like:

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Ok, just one more step to go. Just square root both sides of the equation, this way, we will get ride of the ^2 on A(opposite side), and get A alone.

(\sqrt{A^2}=A)=(\sqrt{25}=5)

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