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zalisa [80]
3 years ago
14

Multiply the polynomials. (x-6)(x^2+2x-4)

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
8 0
I wrote down the answer cuz it’s just easier to read that way:)

yarga [219]3 years ago
3 0

Answer:

x³ - 4x² - 16x + 24

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

x(x² + 2x - 4) - 6(x² + 2x - 4) ← distribute both parenthesis

= x³ + 2x² - 4x - 6x² - 12x + 24 ← collect like terms

= x³ - 4x² - 16x + 24

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What is 7 times as much as the sum of 1/3 + 4/5
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<span>(1/3)(5/5) = (1*5)/(3*5) = 5/15
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3 years ago
A. f(x) = l-2xl - 3<br> Domain: {1, 2, 3}<br> Find the range
gizmo_the_mogwai [7]

Hello there!

We are given the function:

\displaystyle \large{ f(x) =  | - 2x|  - 3} \\

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

<u>x</u><u> </u><u>=</u><u> </u><u>1</u>

\displaystyle \large{ f(1) =  | - 2(1)|  - 3} \\   \displaystyle \large{ f(1) =  | - 2|  - 3} \\

Recall that any numbers in absolute value are always positive.

\displaystyle \large{ f(1) =  2 - 3} \\   \displaystyle \large{ f(1) =   - 1} \\

<u>x</u><u> </u><u>=</u><u> </u><u>2</u>

\displaystyle \large{ f(2) =  | - 2(2)|  - 3} \\   \displaystyle \large{ f(2) =  | - 4 |   - 3} \\   \displaystyle \large{ f(2) =  4 - 3} \\   \displaystyle \large{ f(2) =  1}

<u>x</u><u> </u><u>=</u><u> </u><u>3</u>

\displaystyle \large{ f(3) =  | - 2(3)|  - 3} \\   \displaystyle \large{ f(3) =  | - 6|   - 3} \\   \displaystyle \large{ f(3) =  6 - 3} \\   \displaystyle \large{ f(3) =  3}

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

6 0
3 years ago
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