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3 years ago

Evaluate q = 4 + 8q for q = 8. HELP

Mathematics

1 answer:

Kazeer [188]3 years ago

6 0

Answer:

Step-by-step explanation:

q=−4/7

Hope it helps

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Express 2 times square root 5 as an entire radical

Diano4ka-milaya [45]

2= √4

2×√5 = (√5 × √4)= √20

Answer: √20

Do you have any questions?

7 0

3 years ago

Find a solution to y'(t) = te^-t satisfying the condition y(1) = 1.

Alex_Xolod [135]

Answer:

$y=-e^{-t}(t+1)+1+\frac{2}{e}$

Step-by-step explanation:

The given differential equation is

$y'(t)=te^{-t}$

It can be written as

$\frac{dy}{dt}=te^{-t}$

$dy=te^{-t}dt$

Integrate both sides.

$\int dy=\int te^{-t}dt$

Apply ILATE rule on right side. Here, t is first function and $e^{-t}$ is the second function.

$y=t\int e^{-t}-\int (\frac{d}{dt}t\int e^{-t})$

$y=-te^{-t}-\int (1\times (-e^{-t}))$ $\int e^{-x}=-e^{-x}+C$

$y=-te^{-t}+\int e^{-t}$

$y=-te^{-t}-e^{-t}+C$ .... (1)

Initial condition is y(1) = 1. It means at t=1 the value of y is 1.

$1=-(1)e^{-t}-e^{-(1)}+C$

$1=-e^{-1}-e^{-1}+C$

$1=-2e^{-1}+C$

$1=-\frac{2}{e}+C$

Add $\frac{2}{e}$ on both sides.

$1+\frac{2}{e}=C$

Substitute the value of C in equation (1).

$y=-te^{-t}-e^{-t}+1+\frac{2}{e}$

$y=-e^{-t}(t+1)+1+\frac{2}{e}$

Therefore, the solution of given initial value problem is $y=-e^{-t}(t+1)+1+\frac{2}{e}$ .

4 0

3 years ago

-x+5y=5 graph linear equation

wolverine [178]

THIS IS NOT A LINK USE THE DESMOS GRAPHING CALCULATOR

3 0

3 years ago

A computer that normally costs $890 is on sale with a 35% discount. What is the sale price?

astraxan [27]

Answer:

578.5$

Step-by-step explanation:

first we calculate 35% of $890

890 * 0.35 = 311.5$

Then we subtract 35% from the original price to obtain the final price

890-311.5=578.5$ <---- final price

4 0

3 years ago

I don't understand no this at all

Katena32 [7]

Answer:

Just get the perimeter of the smaller rectangle then times it by 4

Step-by-step explanation:

i tried to use a calculator but i cant do the perimeter of the smaller triangle because i dont know what x is sorry ill try to figure it out.

8 0

3 years ago