Answer:
The volume in such a package is 27648 in³
Step-by-step explanation:
Consider the provided information.
Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 144 in.
Let the dimension are x by x by y.
Where x is the variable for the square base package and y is the variable for length.
Thus l=x, b=x and h=y
Then the volume of the box is:
(∵V=lbh)
The maximum combined length and girth is 144.
Therefore, 

Substitute the value of y in volume of the box.



Substitute V'(x)=0.



Now apply second derivative test.

(Min)
(Max)
Hence, the maximum volume is at x=24
If x=24 then 
Substituting value of x = 24 and y = 48
gives 27648.
Hence, the volume in such a package is 27648 in³
Volume of a cone, V = πr^2h/3
r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum
Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2
Therefore, minimum amount of paper required is 92.95 cm^2
Answer: 88%
Step-by-step explanation:
Answer:1375
Step-by-step explanation:
X= 15 is given
X squared is 15x15 = 225
1600 - 225= 1375
Answer:
√3
Step-by-step explanation:
√12=2√3
-2√3+3√3 = √3
Use calculator to estimate if necessary: 1.7320508075688773