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Law Incorporation [45]
4 years ago
9

Robin randomly selects a number between 1 and 20. What is the probability that the number selected is the square of a natural nu

mber?
Mathematics
2 answers:
icang [17]4 years ago
7 0
All of the natural squares from one to twenty are  1,4,9, and 16. This means there is 4 out of 20 which can be reduced to 1 out of 5 or 20%
denpristay [2]4 years ago
5 0
1 (1x1=1), 4 (2x2=4), 9 (3x3=9), 16 (4x4=16)Probability is 4 out of 20 = 4 / 20, simplified is 1 / 5 (4 into 4 is 1, 4 into 20 is 5)therefore the probability that the number Robin selects randomly is a square of a natural number is 1/5.
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What is y=1/2x +2 y= -x +5 using subsitution
horsena [70]
Y=1/2x+2
y=-x+5
subsitute since they both equal y
1/2x+2=y=-x+5
1/2x+2=-x+5
subtract 2 from both sides
1/2x=-x+3
multiply both sides by 2
x=-2x+6
add 2x to both sides
3x=6
divide both sides by 3
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subsitue
y=-x=5
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3 years ago
How many people will 5 pitchers serve if 1/8 pitcher serves 1 person?
miskamm [114]

Answer:

20 people

Step-by-step explanation:

1/8 serves one so 1/4 does 2 . 1/2 does 3 and 1 does 4 so 4 *5 is 20

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3 years ago
What is an equation of the line that passes through the point (−2,−3) and is perpendicular to the line x+3y=24?
NemiM [27]

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I hope this helped you

3 0
3 years ago
Name all the factors for 1083​
kow [346]

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1, 3, 19, 57, 361, and 1083.

Step-by-step explanation:

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3 years ago
If sin theta = (4)/(7)​, theta in quadrant​ II, find the exact value of (a) cos theta (b) sin (theta + (pi) / (6) ) (c) cos (the
EleoNora [17]

Answer:

a) \cos(\theta) = \frac{\sqrt[]{33}}{7}

b) \sin(\theta + \frac{\pi}{6})\frac{-3\sqrt[]{11}+4}{14}

c) \cos(\theta-\pi)=\frac{\sqrt[]{33}}{7}

d)\tan(\theta + \frac{\pi}{4}) = \frac{\frac{-4}{\sqrt[]{33}}+1}{1+\frac{4}{\sqrt[]{33}}}

Step-by-step explanation:

We will use the following trigonometric identities

\sin(\alpha+\beta) = \sin(\alpha)\cos(\beta)+\cos(\alpha)\sin(\beta)

\cos(\alpha+\beta) = \cos(\alpha)\cos(\beta)-\sin(\alpha)\sin(\beta)\tan(\alpha+\beta) = \frac{\tan(\alpha)+\tan(\beta)}{1-\tan(\alpha)\tan(\beta)}.

Recall that given a right triangle, the sin(theta) is defined by opposite side/hypotenuse. Since we know that the angle is in quadrant 2, we know that x should be a negative number. We will use pythagoras theorem to find out the value of x. We have that

x^2+4^2 = 7 ^2

which implies that x=-\sqrt[]{49-16} = -\sqrt[]{33}. Recall that cos(theta) is defined by adjacent side/hypotenuse. So, we know that the hypotenuse is 7, then

\cos(\theta) = \frac{-\sqrt[]{33}}{7}

b)Recall that \sin(\frac{\pi}{6}) =\frac{1}{2} , \cos(\frac{\pi}{6}) = \frac{\sqrt[]{3}}{2}, then using the identity from above, we have that

\sin(\theta + \frac{\pi}{6}) = \sin(\theta)\cos(\frac{\pi}{6})+\cos(\alpha)\sin(\frac{\pi}{6}) = \frac{4}{7}\frac{1}{2}-\frac{\sqrt[]{33}}{7}\frac{\sqrt[]{3}}{2} = \frac{-3\sqrt[]{11}+4}{14}

c) Recall that \sin(\pi)=0, \cos(\pi)=-1. Then,

\cos(\theta-\pi)=\cos(\theta)\cos(\pi)+\sin(\theta)\sin(\pi) = \frac{-\sqrt[]{33}}{7}\cdot(-1) + 0 = \frac{\sqrt[]{33}}{7}

d) Recall that \tan(\frac{\pi}{4}) = 1 and \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}=\frac{-4}{\sqrt[]{33}}. Then

\tan(\theta+\frac{\pi}{4}) = \frac{\tan(\theta)+\tan(\frac{\pi}{4})}{1-\tan(\theta)\tan(\frac{\pi}{4})} = \frac{\frac{-4}{\sqrt[]{33}}+1}{1+\frac{4}{\sqrt[]{33}}}

5 0
3 years ago
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