The answer is 105, did the assignment got it right
Answer:
B
Step-by-step explanation:
Let point N has coordinates (0,0), then figure A has vertices at points (-3,0), (-7,0), (-7,4) and (-3,4). Figure B has vertices at points (3,1), (7,1), (7,-3) and (3,-3).
1. Translation 10 units to the right has the rule
(x,y)→(x+10,y).
Then vertices of the figure A have images:
- (-3,0)→(7,0);
- (-7,0)→(3,0);
- (-7,4)→(3,4);
- (-3,4)→(7,4).
2. Translation 3 units down has the rule
(x,y)→(x,y-3).
Then images are
- (7,0)→(7,-3);
- (3,0)→(3,-3);
- (3,4)→(3,1);
- (7,4)→(7,1).
As you can see these points are exactly the vertices of the figure B.
Answer:
Step-by-step explanation:
eq. of any line with slope m and passing through (x1,y1) is
y-y1=m(x-x1)
reqd. eq. is
y-1=3/4(x-2)
4y-4=3x-6
4y=3x-6+4
4y=3x-2
so 3.
I got 4.6 after plotting the points on a graph and using pythagorean theorem