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ivolga24 [154]
2 years ago
5

Help with number 14 please :))

Mathematics
1 answer:
Degger [83]2 years ago
3 0

Answer:

b = - 5

Step-by-step explanation:

(k + a )(k + x) +  1 = k^2 + kx + ak + ax + 1

I think the way to solve this is to worry about the 36

k^s + 1 + ak should equal 36

We know that a = 2

k^2 + 1 + 2k = 36

k^2 + 2k + 1 - 36 = 0

k^2 + 2k - 35 = 0

(k + 7)(k - 5) = 0

k = -7   is the only acceptable answer. It is given that K < 0.

bx = kx + ax

b = k + a

b = - 7 + 2

b = - 5

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Would each of them be able to be the side lengths of a triangle?
ratelena [41]
Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²

First posible triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=5                  (5²=25)

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Answer:can be side lengths of a triangle

Second triangle:
 hypotenuse=12.6    (12.6²=158.76)
leg₁=6.7                ( 6.7²=44.89)
leg₂=6.5                  (6.5²=42.25)

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Answer: cannot be side lenghts of a triangle.

third triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=11                  (11²=121)

leg₁²+leg₂²=144+121=265≠169

Answer: cannot be side lenghts of a triangle.

fourth triangle:
hypotenuse=13   (13²=169)
leg₁=6                ( 6²=36)
leg₂=4                  (4²=16)

leg₁²+leg₁²=36+16=52≠169

Answer: cannot be side lenghts of a triangle.
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