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ivolga24 [154]
2 years ago
5

Help with number 14 please :))

Mathematics
1 answer:
Degger [83]2 years ago
3 0

Answer:

b = - 5

Step-by-step explanation:

(k + a )(k + x) +  1 = k^2 + kx + ak + ax + 1

I think the way to solve this is to worry about the 36

k^s + 1 + ak should equal 36

We know that a = 2

k^2 + 1 + 2k = 36

k^2 + 2k + 1 - 36 = 0

k^2 + 2k - 35 = 0

(k + 7)(k - 5) = 0

k = -7   is the only acceptable answer. It is given that K < 0.

bx = kx + ax

b = k + a

b = - 7 + 2

b = - 5

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What is the value of the expression 1 2/3 2/7​
leonid [27]

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1 multiplied by 2/3 and 2/7 is mathematically expressed as 1*2/3*2/7 which is equals to 4/21

4 0
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A rectangle on a coordinate plane has vertices L(0, 6), M(8,6), N(8,0), and O(0, 0). What are the dimensions of the
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3 years ago
Describe two different ways to solve: -10=1/4(8y-12)
timurjin [86]
There are two ways to approach this question. The first is to divide both sides of the equation by 1/4, which is the same as multiplying by 4.
4*(-10)=4*(1/4)(8y-12)
-40=1(8y-12)
-40=8y-12
-40+12=8y-12+12
-28=8y
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-3.5=y
Another method is to distribute 1/4 to each term within the parentheses.
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I hope this is helpful!
3 0
3 years ago
Find the area of the shaded region
kodGreya [7K]

Answer:  21.994 cm²

Step-by-step explanation:

Area of the shaded region = Area of the bigger circle - the areas of the two smaller circles.

Formula for finding area of a circle       =  πr² where π is a constants . It has value of         22/7 or 3.142

Now area of the bigger circle                = 3.142 x 3²

                                                                  = 3.142 x 9

                                                                  = 28.278 cm²                                       Now are of the two smaller triangle        = 3.142 x 1² x 2

                                                                   = 6.284 cm².

Therefore are of the shaded region        = 28.278 - 6.284

                                                                   = 21.994 cm²

7 0
3 years ago
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