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Leviafan [203]
3 years ago
11

A 10-foot ladder leans against a wall with its foot braced 3 feet from wallÍs base. How far up the wall does the ladder reach?

Mathematics
1 answer:
iren2701 [21]3 years ago
5 0
The answer is √91 feet (which is the same as 9.54 feet).

Imagine this as a right triangle. A length of the foot is actually a hypotenuse (c). The distance from wall's base to the ladder foot is one of the sides of the triangle (let it be a).
So, using the Pythagorean theorem:
c² = a² + b²
It is given:
c = 10 feet
a = 3 feet
b = ?
     c² = a² + b²
⇒ 10² = 3² + b²
    100 = 9 + b²
    b² = 100 - 9 = 91
    ⇒ b = √b² = √91 ≈ 9.54 feet
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=> 0.829 = \frac{6}{AC}

=> AC = \frac{6}{0.829}

=> AC = 7.23763570567

=> AC = 7 km

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<h3>Answer : 10 km</h3>

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Genrish500 [490]

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Step-by-step explanation:

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−x=−4

Step 3: Divide both sides by -1.

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kirill115 [55]

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The Piecewise -Defined function and how it is graphed is given below..

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See the attached Graph for better understanding.

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