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3 years ago

Please assist me in the geometry please !!!!

Mathematics

1 answer:

deff fn [24]3 years ago

5 0

Answer:

Solution given:

length of cube[a]=6ft

volume of cube =a³=6³=216ft³

again

For cylinder

d=4ft

r=2ft

h=6ft

volume of cylinder=πr²h=π×2²×6=75.4ft³

Now

remaining volume=216-75.4=<u>140.6ft³</u>

is a required answer.

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HELP PLZZ will give brainliest <3

melisa1 [442]

Answer:

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B}$

$\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}$

$\dfrac{1}{0.5} = \dfrac{4}{\sin B}$

$\sin B = 2$

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

$\dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

$\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}$

$\sin C = \dfrac{8.9\sin 63^\circ}{10}$

$C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}$

$C \approx 52.5^\circ$

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0

4 years ago

Determine whether the biconditional is a true statement.<br><br> |x|=9 if and only if x=9

Charra [1.4K]

Answer:

the biconditional is a true statement

Step-by-step explanation:

The absolute value of x is 9 if it's equal to 9.

(If this is wrong I'm sorry I haven't done this kind of math in a while!)

8 0

4 years ago

Please need help in these 3 algebra questions !!!!

Marysya12 [62]

Answer:

$\large\boxed{7.\ B.\ 8s^2+16s+1}\\\\\boxed{8.\ D.\ -15t^9u^{11}}\\\\\boxed{11.\ C.\ 3,\ -2}$

Step-by-step explanation:

$7.\\(3s^2+7s+2)+(5s^2+9s-1)=3s^2+7s+2+5s^2+9s-1\\\\\text{combine like terms}\\\\=(3s^2+5s^2)+(7s+9s)+(2-1)\\\\=8s^2+16s+1$

$8.\\(-3t^2u^3)(5t^7u^8)=(-3\cdot5)(t^2t^7)(u^3u^8)\qquad\text{use}\ a^na^m=a^{n+m}\\\\=-15t^{2+7}u^{3+8}=-15t^9u^{11}$

$11.\\n-the\ number\\\\n^2=n+6\qquad\text{subtract}\ n\ \text{and}\ 6\ \text{from both sides}\\\\n^2-n-6=0\\\\n^2+2n-3n-6=0\\\\n(n+2)-3(n+2)=0\\\\(n+2)(n-3)=0\iff n+2=0\ \vee\ n-3=0\\\\n+2=0\qquad\text{subtract 2 from both sides}\\n=-2\\\\n-3=0\qquad\text{add 3 to both sides}\\n=3$

4 0

4 years ago

In a online survey, 78% of teens between the ages if 13 and 18 said they own a cell phone. About how many teens own cell phones

Dafna1 [17]

It’s going to be 195 because if you add 55 to 195 it’s going to equal 250

6 0

3 years ago

(-3C^4-5C^2-7C)+(4C^4+8C^3+2C^2) in standard form

posledela

Answer:

C(C^3 + 8C^2 -3C -7)

Step-by-step explanation:

(-3C^4-5C^2-7C)+(4C^4+8C^3+2C^2)

(-3C^4 +4C^4)+8C^3 + ( -5C^2 +2C^2) -7C [Combine like terms]

C^4 + 8C^3 -3C^2 -7C [Simplify]

C(C^3 + 8C^2 -3C -7) [Isolate 1C from the rest]

4 0

3 years ago