Rewrite 7(40 + 2) as the sum of two products.
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Answer:
The Magnitude of charge = q = 15.47 micro coulomb
Step-by-step explanation:
The attractive force between two points q and - 2 q = F = 2.2 Newton
The separation between two charges = 1.4 meters
Now from Coulomb's law = F = where k=
So , 2.2 = (
So , q ² = ()
For charge magnitude
I.e q ² =
so, q =
q = 15.47 \times 10^{-6} c
Or, q = 15.47 micro coulomb
Hence the Magnitude of charge = q = 15.47 micro coulomb Answer