All categories

3 years ago

What is the m and the b

Mathematics

1 answer:

denpristay [2]3 years ago

5 0

The equation is y = mx + b

You might be interested in

HELP PLEASE ITS DUE TOMMOROW AND I HAVE 2 TESTS TO TAKE TODAY D:

Mashcka [7]

Answer:

x=25

x=47

y=25 x=10

y=20

Step-by-step explanation:

2x+10=60

-10 -10

2x=50

2x/2=50/2

x=25

2x+6=100

-6 -6

2x=94

2x/2=94/2

x=47

5y-25=100

+25 +25

5y=125

5y/5=125/5

y=25

11x-30+100=180

11x+70=180

-70 -70

11x=110

11x/11=110/11

x=10

7y-10=3y+70

+10 +10

7y=3y+80

-3y-3y

4y=80

4y/4=80/4

y=20

hopefully this helps :)

8 0

3 years ago

what is the y-intercept of the line perpendicular to the line y=-3/4x+5 that includes the point (-3,-3)?

Deffense [45]

Answer:

Step-by-step explanation:

For this question, your friend is the point-slope form.

Point-slope form = $y-y_1 = m(x-x_1)$

The only variables you replace are m = slope, y1 = y of a given point, and x1 = x of a given point.

First, we need to find the slope that is perpendicular to the equation $y=-\frac{3}{4}x+5$

An equation that is perpendicular to another equation have to be negative reciprocals (negative inverse) of each other.

If the slope is 3, then the negative reciprocal of 3 is $-\frac{1}{3}$ .

So, since the given slope is -3/4, the negative reciprocal is $\frac{4}{3}$ .

We will use the negative reciprocal as m since we are trying to find the equation of line that includes (-3, -3) and is perpendicular to the other equation.

We will use point slope form using the (-3, -3) points and negative reciprocal as m.

$y-y_1 = m(x-x_1)\\y-(-3) = \frac{4}{3} (x-(-3))\\y+3=\frac{4}{3}(x+3)$

Now, we need to convert this into slope-intercept form. The reason why we need to do this is because y = mx + b, where b is the y-intercept. To do this, solve for y - or in other words, isolate y..

$y+3=\frac{4}{3}(x+3)\\y+3=\frac{4x}{3}+4\\y+3-3=\frac{4x}{3}+4-3\\y=\frac{4}{3}x+1$