What is the simplified form of 2/x^2-x - 1/x?

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

8 0

Answer: $\bold{(C)\ \dfrac{3 - x}{x(x-1)}}$

Step-by-step explanation:

$\dfrac{2}{x^2-x}-\dfrac{1}{x}$

$=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}$

$=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}\bigg(\dfrac{x-1}{x-1}\bigg)$

$=\dfrac{2}{x(x-1)}+\dfrac{-x+1}{x(x-1)}$

$=\dfrac{2-x+1}{x(x-1)}$

$=\dfrac{3-x}{x(x-1)}$

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