This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.
∴N(c₁) =

N(c₂) =

∴N(c₁c₂) =

∴ Number of positive integers that are not divisible by 4 or 6,
N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4
You'll have to multiply 0.7 by 120.
120*0.7 = n
n is the number that is 70% of 120
120 * 0.7 = 84
Hope this helps :)
Well. I can't see the picture. But it would be decreasing at a rate of 4 so pick a point on the any line move over to the right one, then down four. And for the y intercept the line would intersect the y axis at positive one. Sorry if that's confusing
Answer:
![\sqrt[3]{x^{2}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D)
Step-by-step explanation:
![x^{2/3} = \sqrt[3]{x^{2}}](https://tex.z-dn.net/?f=x%5E%7B2%2F3%7D%20%3D%20%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D)
To find the X value of the solution, you would set the two equations equal to each other bu substitution:
if <span>y = -2x + 5 and y = 3x - 2,
</span>-2x + 5 must be equal to 3x - 2
solve for x... you should get 7/5
then, plug that into one of the original equations as X and you would get the Y value, 11/5
This point, (7/5,11/5) is where the two lines cross