Answer:
Step-by-step explanation:
system of equations… so, in the first one, let x =amount of ticket A, let y = amount of ticket B.
So, x + y = 300 tickets
In equation two, we know $12 per ticket A, and $15 per ticket B, but we don’t know the amount of tickets.
So, $12x + $15y = $4,140.
So we can solve this using elimination, substitution, graphing it etc. etc.
I will use substitution, as I prefer that when I have one equation that is x +/- y =
so i prefer multiplying by 15, so I am going to solve for y.
x + y = 300
-x ……. -x
y = -x +300
No substitute the y value into the second equation…
$12x +$15(-x + 300) =$4,140.
so we distribute the 15
12x -15x + 4500 = 4140
combine like terms:
-3x +4500 = 4140
subtract 4500 from both sides
-3x = -360
divide both sides by -3
x = 120. So we know that there were 120 of tickets A bought
so we go back to our system and solve
x + y = 300, but use our newly acquired x value.
120 + y = 300
y = 180
So, 120 of ticket A, 180 of ticket B, and we could plug it in and get the same answer….. just for fun
12x + 15y = 4140
12 (120) + 15 (180)
1440 + 2700 = 4140.
