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12345 [234]
3 years ago
15

Paulo took out a $900 loan using an 12% simple interest rate for a period of 9 months. What the effective annual interest rate f

or the loan? Give your answer as a percentage to the nearest tenth of a percent.
Mathematics
2 answers:
Dovator [93]3 years ago
6 0

Answer:

13.2

Step-by-step explanation:

vekshin13 years ago
5 0

Answer:

12.68%

Step-by-step explanation:

To calculate effective annual interest rate we need to use the following formula:

i=(1+\frac{r}{m})^m-1

Where, 'i' is the effective annual interest rate

'r' is the annual rate of interest

'm' is the frequency of compounding.

When there is continuous compounding the effective annual rate uses the following formula:

i=e^r-1

In our case we would are assume that there is continuous compounding since no information regarding the frequency of compounding is given:  

Plugging r=12%=0.12, we get:

i=e^{0.12}-1

i=1.1274-1=0.1274

i=0.1274

i=12.74\%

Therefore, the effective annual interest rate is 12.74%.

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bazaltina [42]

Answer:

C

Step-by-step explanation:

First cuz the y-intercept is 3 so not B or D

And the slope is -2/3

so the answer is C.

i'm not really sure about the slope part.

3 0
3 years ago
Read 2 more answers
5n + 3n<br> simplify each expression
Setler79 [48]

Answer: 8n

Step-by-step explanation: 5n + 3n

3 0
3 years ago
Each teacher can order 3 boxes of pencils for the school year. If 3 boxes together hold 82 pencils how many are in each box? If
SashulF [63]
There are 27 & 1/3 pencils in each box. Each student will get 3 pencils per year. There will be 16 pencils left over.
6 0
3 years ago
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What is the simplest form of this expression? (x + 7)(3x − 8)
Komok [63]
Answer: 3x^+13x-56
Steps
1). Multiply the parentheses
(X+7)(3x-8)
=X x 3x -8x+7 x 3x -7 x 8
2). Multiply
3x^-8x + 21x - 56
3). Do like terms
3x^+13x - 56
4). Solution
[3x^+13x - 56]

-HOPE THAT HELPEDED <3

4 0
4 years ago
F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
2 years ago
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