Let they be x.
Cost of textbooks + laptops cant greater than total amount.
(cost of 1 textbooks * number of textbooks) + (cost of 1 laptop * number of laptops ≤ 6500
(30*116) + (x*439) ≤ 6500
3480 + 439x ≤ 6500
439x ≤ 3020
x ≤ 6.8(approx)
Last natural number is 6, says, they can buy 6 laptops at max.
Answer:
5/26.
If you count y as a vowel it is 3/13
Step-by-step explanation:
Faces are correct, edges are correct, and vertices are also correct
Answer:
80000
Step-by-step explanation:
Here, we want to write the number in one significant figure
What we have to do here is to simply turn the numbers after 8 to zero
This is because the first number is less than 5
So we have the significant figure as 80000
First put a y in the place of f(x)
y = (1/3)^x
Then switch x and y
x = (1/3)^y
Solve for y
ln(x) = yln (1/3)
simplify
ln(x) = -ln(3)y
solve
y = -ln(x)/ln(3)
