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3 years ago

Match these terms with their definitions.

Physics

2 answers:

Tomtit [17]3 years ago

8 0

1. Entropy

2. Thermodynamics

3. First law of thermodynamics

4. Second law of thermodynamics

5. Maximum entropy

6. The kinetic and potential energy of molecules of a substance

adoni [48]3 years ago

7 0

The correct matches are as follows:

1. measure of disorder
entropy

2. the study of energy conversions
thermodynamics

3. conservation of energy when heat is added
second law of thermodynamics

4. disorder increasing
the kinetic and potential energy of the molecules of a substance

5. reaching a state of total disorder
maximum entropy 

6. internal energy
first law of thermodynamics

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The capacitance is $4.484\times10^{-12}\ F$

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Explanation:

Given that,

Area =7.70 cm²

Distance = 1.50 mm

Potential difference = 25.0 V

Suppose we find the electric field between the plates, the surface charge density, the capacitance and the charge on each plates.

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Using formula of electric field

$E=\dfrac{V}{d}$

Put the value into the formula

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Using formula of charge density

$\sigma=E\times\epsilon_{0}$

Put the value into the formula

$\sigma=16666.66\times8.85\times10^{-12}$

$\sigma=1.474\times10^{-7}\ C/m^2$

We need to calculate the capacitance

Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times7.60\times10^{-4}}{1.50\times10^{-3}}$

$C=4.484\times10^{-12}\ F$

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Using formula of charge

$q=CV$

Put the value into the formula

$q=4.484\times10^{-12}\times25.0$

$q=112.1\times10^{-12}\ C$

Hence, The electric field is 16666.66 V/m.

The surface charge density is $1.474\times10^{-7}\ C/m^2$

The capacitance is $4.484\times10^{-12}\ F$

The charge on each plate is $112.1\times10^{-12}\ C$

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