AAaaahh yes, T'was that a lovely chap by the name of Copernicus, has discovered us a little secret, well. why dont you share?
Copernicus: well uh, i'm a bit shy
ME: who a gives a flying *bleep* about your feelings man! just man up an discover the earth's rotation already!
Answer:
A_f= 15,769 m²
Explanation:
Este es un ejercicio de dilatación térmica,
ΔA = (2α) A₀ ΔT
el arrea de recipiente
A₀ = L A
A₀ = 3,5 4,5
A₀= 15,75 m²
el coeficiente de dilatación térmica es alfa = 16,6 10⁻⁶ C⁻¹
calculemos
ΔA = 2 16,6 10⁻⁶ 15,75 ( 40 -4)
ΔA = 522,9 (36) 10⁻⁶
A= 1,88 10⁻² m2
el cambio de volumen es
ΔA = A_f – A₀
A_f = A₀ + ΔA
A_f= 15,75 +1,88 10⁻²
A_f= 15,769 m²
Answer:
2d
Explanation:
For any instance equivalent force acting on the body is

Where
m is the mass of the object
k is the force constant of the spring
d is the extension in the spring
and
d/dt(dx/dt)= is the acceleration of the object
solving the above equation we get

where

A is the amplitude of oscillation from the mean position.
k= spring constant , T= time period
Here we are assuming that at t=T/4
x= 0 since, no extension in the spring
then
A=- d
Hence
x=- d sin wt + d
now, x is maximum when sin wt=- 1
Therefore,
x(maximum)=2d
Answer:
P = 7500 [W]
Explanation:
First We must use Newton's second law to find the force. Newton's Second Law tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
m = mass = 150 [kg]
a = acceleration = 5 [m/s²]
![F = 150*5\\F = 750 [N]](https://tex.z-dn.net/?f=F%20%3D%20150%2A5%5C%5CF%20%3D%20750%20%5BN%5D)
We know that the work is determined by multiplying the force by the distance, in this way the units of the work are [N*m] which corresponds to 1 Joule [J].
And the power is determined by dividing the work by the time, in this way we have that [J/s] corresponds to 1 [W].
We must convert the speed from kilometers per hour to meters per second.
![36[km/hr]*1000[\frac{m}{1km}]*[\frac{1hr}{3600s} ]=10 [m/s]](https://tex.z-dn.net/?f=36%5Bkm%2Fhr%5D%2A1000%5B%5Cfrac%7Bm%7D%7B1km%7D%5D%2A%5B%5Cfrac%7B1hr%7D%7B3600s%7D%20%5D%3D10%20%5Bm%2Fs%5D)

where:
P = power [W]
F = force = 750 [N]
v = 10 [m/s]
![P = 750*10\\P = 7500 [W]](https://tex.z-dn.net/?f=P%20%3D%20750%2A10%5C%5CP%20%3D%207500%20%5BW%5D)