Question

The angle of elevation of the sun (the angle the rays of sunlight make with the flat ground) at 10:00 a.m. is 29°. At that point, a tree’s shadow is 32 feet long. How tall is the tree?

Answer 1

Answer:

Height of the tree is approx 17.74 feet.

Step-by-step explanation:

the angle of elevation of the sun at 10:00 a.m. is 29°.

Then measure of angle C = 29°

At that point, a tree’s shadow is 32 feet long.

Then BC=32

Now we need to find about how tall is the tree.

So we can use trigonometric formula of right triangle to find missing height (x) of side AB.

$\tan\left(C\right)=\frac{AB}{BC}$

$\tan\left(29^o\right)=\frac{x}{32}$

$\tan\left(29^o\right)=\frac{x}{32}$

$0.55431=\frac{x}{32}$

$0.55431*32=x$

$17.73792=x$

Hence height of the tree is approx 17.74 feet.