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Mathematics

2 answers:

Softa [21]3 years ago

6 0

First, find the area of the whole square
9 x 9 = 81
----------------------------
Now find the area of the triangles. Two triangles equal 1 square since the triangles are 3 feet on one side and one another, the area of two triangles is 9, or 4.5 for one
Now multiply by 2 or 4 depending on which number you decide ( 9 or 4.5)
9 x 2 = 18
4.5 x 4 = 18
--------------------------------------------
Now subtract
81 - 18 = 63
63 is your answer

ANEK [815]3 years ago

3 0

area of square = 9 x 9 = 81 square feet

area of 1 corner = 1/2 * 3 * 3 = 4.5 square feet

4.5 * 4 = 18 square feet total of all 4 corners

81 - 18 = 63 square feet total not covered by benches.

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Write the rule for the nth term of the following sequence.

denis-greek [22]

Answer:

$2^{n-3}$ is the nth term of the given sequence.

Step-by-step explanation:

The sequence given is

$\frac{1}{4},\frac{1}{2},1,2,4 .....$

We can clearly see that 1st term is $\frac{1}{4}$ and 2nd term is $\frac{1}{2}$

2nd term is obtained by multiplying the 1st term by 2.

2nd term is $\frac{1}{2}$ and 3rd term is 1.

3rd term is obtained by multiplying the 2nd term by 2.

3rd term is 1 and 4th term is 2.

4th term is obtained by multiplying the 3rd term by 2.

Clearly, the given series is a Geometric Progression(GP) with

First term, $a = \frac{1}{4}$

Common Ratio, $r = 2$

We know that $n^{th}$ term for a GP is:

$a_n = ar^{n-1}$

Putting values of a and r

$a_n = \dfrac{1}{4}2^{n-1}\\a_n = \dfrac{1}{2^{2} }2^{n-1}\\a_n = 2^{n-1-2}\\a_n = 2^{n-3}$

Hence, $2^{n-3}$ is the nth term of the given sequence.

3 0

2 years ago

HELLLLLLLLLLLLLLLLLLLLLP

kkurt [141]

So 10/2 simplified is 5/1 which is on point 5. -9/2 is already simplified so in decimal form it is -4.5 which is -4 1/2, so you go down from 0 and mark it right where the BLUE dot is and the GREEN dot is 5/1. Hope this helps! :)