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3 years ago

Can a pyramid have rectangles as lateral faces?

2 answers:

4 0

No, it is not possible to have rectangular lateral sides. A pyramid is formed with a polygonal base (aka a base that is a polygon) and the lateral sides are triangles. The lateral sides of any pyramid are always triangles. The triangular faces all meet at the apex point, which is the highest point on the pyramid.

Side Note: The pyramids in Egypt are an example of a rectangular pyramid. This is a pyramid with a rectangular base.

mezya [45]3 years ago

3 0

Answer is no, only the base can be a rectangle

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Tina bought 20 apples and bananas for her class. Apples cost $1.50 each. Bananas cost $1.25 each. Tina spent $28 in all. How man

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Tina bought 12 bananas and 8 apples

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3 years ago

Brandon bought 6 toy cars. The cars came in p packages. Write an expression that shows how many toy cars were in each package.

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Well in order to find how many toy cars were in each package you would need to divide the number of toy cars by the number of packages. So your expression would be p / 6.

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3 years ago

A certain company sends 40% of its overnight mail parcels by means of express mail service A1. Of these parcels, 4% arrive after

Harrizon [31]

Answer:

(a) The probability that a randomly selected parcel arrived late is 0.026.

(b) The probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(d) The probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

Step-by-step explanation:

Consider the tree diagram below.

(a)

The law of total probability sates that: $P(A)=P(A|B)P(B)+P(A|B')P(B')$

Use the law of total probability to determine the probability of a parcel being late.

$P(L)=P(L|A_{1})P(A_{1})+P(L|A_{2})P(A_{2})+P(L|A_{3})P(A_{3})\\=(0.04\times0.40)+(0.01\times0.50)+(0.05\times0.10)\\=0.026$

Thus, the probability that a randomly selected parcel arrived late is 0.026.

(b)

The conditional probability of an event A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

Compute the probability that a parcel was late was being shipped through the overnight mail service A₁ as follows:

$P(A_{1}|L)=\frac{P(L|A_{1})P(A_{1})}{P(L)} \\=\frac{0.04\times 0.40}{0.026} \\=0.615$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{2}|L)=\frac{P(L|A_{2})P(A_{2})}{P(L)} \\=\frac{0.01\times 0.50}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{3}|L)=\frac{P(L|A_{3})P(A_{3})}{P(L)} \\=\frac{0.05\times 0.10}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

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3 years ago

Jada researched the average rainfall in April for several different locations. This list shows her findings.

Georgia [21]

Answer:

it's correct

Step-by-step explanation:

there is one in 1 2/4 , one in 2 and 3 in 2 1/2

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2 years ago

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Tim would be 75 and JOAnne would be 70 years

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3 years ago

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