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harina [27]
3 years ago
10

First write a method to calculate the greatest common divisor (GCD) of two positive integers using Euclid’s algorithm (also know

n as the Euclidean algorithm). Then write a main method that requests two positive integers from the user, validates the input, calls your method to compute the GCD, and outputs the return value of the method (all user input and output should be done in main). Check Wikipedia to find more information about GCDs1 and Euclid’s algorith
Computers and Technology
1 answer:
MAVERICK [17]3 years ago
7 0

Answer:

import java.util.Scanner;

public class Gcd

{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 System.out.print("Enter two numbers to find their GCD: ");

 int number1 = input.nextInt();

 int number2 = input.nextInt();

 

 if(number1 > 0 && number2 > 0)

     System.out.println("GCD of " + number1 +" and " + number2 +" is: " + findGCD(number1, number2));

       else

           System.out.println("Invalid Input!");

}  

public static int findGCD(int number1, int number2) {

    if(number2 == 0){

        return number1;

    }

return findGCD(number2, number1 % number2);

}

}

Explanation:

To be able to find GCD, we need to factorize the numbers and multiply common factors.

- <u>Inside the function:</u>

- Recursively divide <em>number1</em> by <em>number2</em> until <em>number2</em> is equal to zero.

- Return <em>number1</em>  when the <em>number2</em> is equal to zero. That means we found all the divisors of <em>number1</em>

- <u>Inside the main:</u>

- Ask user to input numbers

- Check if both numbers are greater than zero

- If they satisfy the condition, call the method and print the result.

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Answer:

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// the timeEnd and timeStart variables are passed by pointer

void UpdateTimeWindow(int* timeStart, int* timeEnd, int offsetAmount){

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Explanation:

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