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3 years ago

Jack has some marbles. He has ten more red marbles than blue marbles. He has fewer yellow marbles than blue marbles.

Mathematics

1 answer:

kap26 [50]3 years ago

5 0

Answer:

Jack has at least 15 marbles: 12 red, 2 blue and 1 yellow.

Step-by-step explanation:

1. Let's review the information given to us to solve the problem correctly:

Number of red marbles = 10 more than blue marbles

Number of yellow marbles fewer than blue marbles

2. How many of each color marble could Jack have?

r = Number of red marbles

b = Number of blue marbles

y = Number of yellow marbles

r = b + 10

y < b

If y = 1, then b ≥ 2, and r = b + 10,

fulfilling the three conditions, we have:

y = 1, b = 2, and r = 12

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3 years ago

Read 2 more answers

Find the 96th term of the arithmetic sequence 1, -12, -25, ...1,−12,−25,

IrinaK [193]

Answer:

$a_9_6=-1,234$

Step-by-step explanation:

we know that

The rule to calculate the a_n term in an arithmetic sequence is

$a_n=a_1+d(n-1)$

where

d is the common difference

a_1 is the first term

n is the number of terms

we have

$1,-12,-25,...$

Remember that In an Arithmetic Sequence the difference between one term and the next is a constant. and this constant is called the common difference

$a_1=1\\a_2=-12\\a_3=-25$

$d=a_2-a_1=-12-1=-13$

Find the 96th term of the arithmetic sequence

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we have

$a_1=1\\d=-13\\n=96$

substitute

$a_9_6=1+(-13)(96-1)$

$a_9_6=1+(-13)(95)$

$a_9_6=1-1,235$

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2 years ago

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4 years ago

the music hall has 20 boxes on thurs 2/5 were occupied, on friday 2/4 were occupied and o saturday 8/10 were occupied. Using sym

NikAS [45]

1. The music hall has 20 boxes :
=> on thurs 2/5 were occupied
=> on friday 2/4 were occupied
=> and on saturday 8/10 were occupied.
Let’s find out which day has the most occupied space of the music hall.
2/5 + 2/4 + 8/10 = 6/20 + 7/20 + 10/20
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3 years ago